我在 R 中有一个名为 df 的数据框,我之前在另一个关于
gt()
的问题中使用过它,并且在 R 中找到了 here .
df = structure(list(projects = c("Restaurant, Pizzeria and Pasta House Works for New York",
"London Project - New Restaurant Project",
"Athens - Beautiful Lands for Aigaleo City Project",
"Berlin City - Exhibition near the airport with restaurants",
"Pizzeria Buenos Aires New italian restaurant - pasta, tartufo and vino",
"area mean value", "total mean value"),
happiness.and.joyfullness = c(3.5,4, 3, 3.2, 4, 5, 3),
joy.for.children = c(3, 5, 3, 4, 5,4, 4),
area = c(3, 5, 3, 3, 3, 4, 4),
damages.from.environment = c(2,4, 2, 3, 3, 5, 5),
approach = c(3, 1, 5,3, 5, 5, 4),
expensive = c(3, 5, 3, 4, 5, 5, 5),
safety.comes.first = c(5,5, 5, 5, 5, 5, 4),
hungry = c(3, 5, 2, 4, 5,5, 5)),
row.names = c(NA, -7L),
class = c("tbl_df", "tbl","data.frame"))
列名是非常大的文本,我想被换行。所以我找到了一个办法:
df%>%
gt()%>%
cols_label("happiness.and.joyfullness" = md("happiness<br />and<br />joyfullness"))%>%
cols_label("joy.for.children" = md("joy<br />for<br />children"))%>%
cols_label("damages.from.environment" = md("damages<br />from<br />environment"))%>%
cols_label("safety.comes.first" = md("safety<br />comes<br />first"))
问题是我想将它们居中对齐第一行并将其加粗。
如何使用 gt 库在 R 中做到这一点?
首先,不需要单独的
cols_label
。您可以使用 cols_align
和 tab_style
来获得您想要的更改。
df %>%
gt() %>%
cols_label(
projects = "projects",
happiness.and.joyfullness = md("happiness<br />and<br />joyfullness"),
joy.for.children = md("joy<br />for<br />children"),
damages.from.environment = md("damages<br />from<br />environment"),
safety.comes.first = md("safety<br />comes<br />first")
) %>%
cols_align(align = "center", columns = c(projects)) %>%
tab_style(
style = cell_text(weight = "bold"),
locations = list(
cells_column_labels(columns = c(projects)),
cells_body(columns = c(projects))
)
)