URLSession 的 dataTask 未运行

问题描述 投票:0回答:2

我正在尝试从 API 获取结果,但运行请求本身时遇到问题。

这是我目前拥有的代码:

let url = URL(string: "https://httpbin.org/get")!
let task = URLSession.shared.dataTask(with: url) { (data, response, error) in
if let error = error {
        print("error: \(error)")
    } else {
        if let response = response as? HTTPURLResponse {
            print("statusCode: \(response.statusCode)")
        }
        if let data = data, let dataString = String(data: data, encoding: .utf8) {
            print("data: \(dataString)")
        }
    }
}
task.resume()

但是,它似乎没有在 dataTask 的代码块内运行任何内容。

感谢您的帮助:)

ios swift iphone
2个回答
1
投票

您的代码运行良好。看来您只是错误地调用了该函数...尝试这样:

1:

    func request() {
    let url = URL(string: "https://httpbin.org/get")!
    let task = URLSession.shared.dataTask(with: url) { (data, response, error) in
    if let error = error {
            print("error: \(error)")
        } else {
            if let response = response as? HTTPURLResponse {
                print("statusCode: \(response.statusCode)")
            }
            if let data = data, let dataString = String(data: data, encoding: .utf8) {
                print("data: \(dataString)")
            }
        }
    }
    task.resume()
}

2:

    override func viewDidLoad() {
    super.viewDidLoad()

    request()
}

0
投票

尝试使用数据 JSONSerialization 对我有用

块引用

func callApi(){
let session = URLSession.shared
let url = URL(string: "https://jsonplaceholder.typicode.com/todos/1")
let task = session.dataTask(with: url!) { (serviceData, urlReponse, error) in
    guard error == nil else{
        print(error!)
        return
    }
    if let response = urlReponse as? HTTPURLResponse {
        print("statusCode \(response.statusCode)")
    }
    if let data = serviceData, let dataString = String(data: data, encoding: .utf8){
        print("String Format" + dataString)
    }

    // Data Parse
    
    let jsonData = try? JSONSerialization.jsonObject(with: serviceData!, options: .mutableContainers)
    let result = jsonData as! Dictionary<String, Any>
    print("Dictionary Format \(result)")
}
task.resume() }
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