如果循环在不需要时重复自身

Question

我最近遇到了一个问题，该代码将在第69行附近重复出现。我不知道为什么会这样，任何帮助都将是惊人的。这是代码。

import time
import threading
import random


totalviews = 0
videoViews = 0
totallikes = 0
videolikes = 0
totaldislikes = 0
videodislikes = 0
subscribers = 0
videolength = 0
midroles = 0
uploadTimer1 = 0
waitTimer1 = 0
x = 0
comadymins = 0
comadysecs = 0


def timer1():
    global uploadTimer1
    global waitTimer1
    global x
    time.sleep(.75)
    if x == 1:
        print(uploadTimer1, 'mins remaining')
        uploadTimer1 -= 1
        time.sleep(60)
        if uploadTimer1 == 0:
            x = 0


Timer1 = threading.Thread(target=timer1)

print('')
print("you decided to start a youtube channel")
while True:
    time.sleep(1.25)
    print('')
    print('what type of video will you make')
    print('1. comedy')
    print('2. gaming')
    print('3. science')
    print('4. check timer')
    UserInput = input('')
    if UserInput == '1':
        if waitTimer1 == 0:
            comadymins = random.randint(10, 30)
            comadysecs = random.randint(0, 60)
            time.sleep(0.1)
            print('video length will be', comadymins, ":", comadysecs)
            time.sleep(1)
            if comadymins <= 29 and comadysecs <= 59:
                print('would you like to upload now?')
                time.sleep(.5)
                UserInput = input('')
                if UserInput == 'y':
                    print('video is uploading')
                    print('it will take 4 mins')
                    uploadTimer1 += 4
                    x += 1
                    Timer1.start()
                    waitTimer1 += 1
                else:
                    print('okay')
            if comadymins <= 19 and comadysecs <= 59:
                print('would you like to upload now?')
                time.sleep(.5)
                UserInput = input('')
                if UserInput == 'y':
                    print('video is uploading')
                    print('it will take 4 mins')
                    waitTimer1 += 1
                    uploadTimer1 += 4
                    x += 1
                    Timer1.start()
                else:
                    print('okay')
        else:
            print('you already have a video running')
            time.sleep(1)

    if UserInput == '4':
        print('okay')
        print(uploadTimer1, "mins remaining")

任何帮助都将是惊人的。我对编码也很陌生，因此如果代码混乱或不符合平均标准，将感到抱歉。我只编写了大约一个月的代码，如果您有任何令人惊奇的建议，每周大约要进行3个小时。

Answer 1

[状态为while True:时，您有一个无限循环这将永远贯穿它下面的所有线条。如果满足特定条件，可以通过在循环内添加一个中断来退出此循环。

Answer 2

您的问题是，您拥有相同的打印数据，“您现在要上传吗？”和两个条件语句，它们的行为方式相同。你有一个

if comadymins <= 29 and comadysecs <= 59:

和一个

if comadymins <= 19 and comadysecs <= 59:

因为您在这里有一个随机数：

comadymins = random.randint(10, 30)

类似于“ 11”同时小于“ 19”和“ 29”，因此您的两个条件都将触发，并且您会看到重复的句子“您现在要上传吗？”。您应该按照问题的逻辑进行工作。