请帮助我使用右对齐的哈希值和空格正确打印高度为“n”的金字塔。我已在下面发布了代码本身。该程序正确地要求用户输入，但不会构建右对齐的金字塔。如果有人可以解决这个问题，请帮忙。
#include <stdio.h>
#include <cs50.h>
int main(void)
{
int i=0;
int n=0;
do
{
printf("Height:");
n=GetInt();
} while (n<0 || n>23);
for (i=0; i<n; i++)
{
printf(" ");
for (int x=0; x<i+2; x++)
{
printf("#");
}
printf("\n");
}
return 0;
}
这是正确的解决方案之一！
#include <stdio.h>
#include <cs50.h>
void buildPyramid(int height);
int main(void)
{
// Initialize the variable height
int height;
// Run the loop to get a value of height between 1 and 8, inclusive, from the user
do
{
height = get_int("Height: ");
}
while (height < 1 || height > 8);
// Call the function and pass height to it as a parameter
buildPyramid(height);
}
// Declare the function buildPyramid
void buildPyramid(int height)
{
// Loop to add a new line
for (int i = 0; i < height; i++)
{
// Loop to add spaces
for (int k = height - i; k > 1; k--)
{
printf(" ");
}
// Loop to add hashes
for (int j = 0; j <= i; j++)
{
printf("#");
}
printf("\n");
}
}
#include<cs50.h>
#include<stdio.h>
#include<stdio.h>
void half_pyramid(int n);
int main(void){
int height;
do{
height = get_int("Height: ");
}while(height<=0||height>23);
half_pyramid(height);
}
void half_pyramid(int n)
{
int spaces;
int dashes;
for(int i = 2; i<=n+1;i++){
for(spaces = (n-i); spaces>=0;spaces--){
printf(" ");
}
for (dashes = 1; dashes <= i; dashes++){
printf("#");
}
printf("\n");
}
}
#include <cs50.h>
#include <stdio.h>
int main(void)
{
int height;
int spaces;
int hash;
do
{
height = get_int("Height: ");
}
while (height < 0 || height > 23);
for (int i = 0; i < height; i++)
{
// For loop to print out the spaces
for (spaces = (height - i); spaces >= 2; spaces--)
{
printf(" ");
}
// For loop to print out hashes
for (hash = 0; hash <= (i + 1); hash++)
{
printf("#");
}
printf("\n");
}
}
int main(void){
int height;
int spaces;
int dashes;
do
{
printf("Height:");
height = GetInt();
}
while (height <= 0 || height >= 23);
//loop for the rows
for (int i = 1; i <= height; i++){ //fixed the <= part of the operator
//loop for the spaces and dashes per row
for (spaces = (height - i); spaces >= 0; spaces--){
printf(" ");
}
for (dashes = 1; dashes <= (i + 1); dashes++){
printf("#");
}
printf("\n");
}
return 0;
}
在你的主循环中你有：
// Instruction for printing 1 space
// Sub loop for printing x+1 number of hashes
// Instruction for printing a new line
因此，每次循环时，它都会正确绘制哈希值和新行，但您不会告诉它每次绘制超过 1 个空格，因为与哈希值的子循环不同，指令不会随着每次传递而增加。
#include<stdio.h>
#include<cs50.h>
int main (void)
{
int height;
int c = 0;
do
{
printf("Height?\n");
height = GetInt();
}while(height < 0 || height > 23);
for(int a = height; a > 0; a--)
{
for(int b = 0; b < a - 1; b++)
{
printf(" ");
}
printf("#");
c++;
for (int d = 0; d < c; d++)
{
printf("#");
}
printf("\n");
}
}
这是我如何用两侧解决这个问题的版本，但你可以让它只用一个，只需使用 2 个 for 循环而不是 3 个。
如果我们必须将数字 1 – 8 作为输入，即金字塔的高度，我们可以使用一个 for 循环来打印金字塔的每一行。
在这个循环中，我们需要另外两个 for 循环来打印空格和哈希值。
由于我们还需要金字塔的另一边，因此我们将在主循环中总共使用三个循环。
为什么是三个循环而不是四个？因为我们实际上不需要在金字塔右侧打印空间。
除了高度变量之外，我们还需要另一个作为计数器，因为我们无法操纵高度变量。
这些 for 循环以相反的方向工作，即我们拥有的空间越多，我们打印的哈希值就越少，反之亦然。
所以，最终的 CS50 Pset 1 Mario More 解决方案看起来就像这样：
#include <cs50.h>
#include <stdio.h>
int main(void)
{
int height;
do {
height = get_int("Height: ");
}
while (height < 1 || height > 8);
if (height > 0 || height < 9) {
int counter = 0;
for (int row=0; row<height; row++) {
if (counter != height) {
for (int spaces = (height-1) - counter; spaces > 0; spaces--) {
printf(" ");
}
for (int hashes = 0; hashes <= counter; hashes++) {
printf("#");
}
//ignore this block below if you want only one side
printf(" ");
for (int hashes = 0; hashes <= counter; hashes++) {
printf("#");
}
//##################################################
printf("\n");
counter++;
}
}
}
}
我实际上写了一篇关于此的博客文章，因为我喜欢记笔记，以防您需要更多信息。
这就是我如何让它为马里奥更舒适地工作。
#include <cs50.h>
#include <stdio.h>
int main(void)
{
int n;
do
{
n = get_int("Height: ");
}
while (n < 1 || n > 25);
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
if (i + j < n - 1)
printf(" ");
else
printf("#");
}
printf(" ");
for (int j = 0; j < n; j++)
{
if (n - i < j + 2)
printf("#");
}
printf("\n");
}
}
#include<cs50.h>
#include<stdio.h>
int main()
{
int n;
do
{
n = get_int("Height: ");
}
while (n < 1);
for (int i = 0; i<n; i++)
{
for (int j = 0; j < i+1; j++)
{
printf("#");
}
printf("\n");
}
}
我认为您的代码在最后一个原始数据中将无法正常工作，因为第二个循环从为每个 i 迭代自动添加一个空块开始，但是构建基本原始数据的最后一个 i 迭代没有任何空块，但只有#s。 代码应该看起来更像这样：
#include <cs50.h>
#include <stdio.h>
int main(void)
{ int height;
do {
height = get_int("height: ");
}
while (height<1 || height>8);
int i, j;
for ( i = 0; i < height; i++) {
for ( j = 0; j < height; j++) {
if (j + i < height - 1) {
printf(" ");
} else {
printf("#");
}
}
printf("\n");
}
}
#include <cs50.h>
#include <stdio.h>
int main(void)
{
// Get positive integer from user
int height;
do
{
height = get_int("Height: ");
}
while (height < 1 || height > 8);
//for loop for next line
for (int hash = 1; hash < height + 1; hash++)
{
for (int space = height - hash; space > 0; space--) // for loop to add spaces
{
printf(" ");
}
for (int hashwidth = 0; hashwidth < hash; hashwidth++)// for loop to add hashes
{
printf("#");
}
printf("\n");
}
}
上述问题可以使用 Stephen Prata 的 C Primer Plus 书中所谓的 width.c 程序来解决吗？
/* width.c -- field widths */
#include <stdio.h>
#define PAGES 959
int main(void)
{
printf("*%d*\n", PAGES);
printf("*%2d*\n", PAGES);
printf("*%10d*\n", PAGES);
printf("*%-10d*\n", PAGES);
return 0;
}
#include<cs50.h>
#include<stdio.h>
int main()
{
int n;
do
{
n = get_int("Height: ");
}
while (n < 1 || n > 8);
for (int i = 0; i<n; i++)
{
for (int k=n-i; k>1 ; k--)
{
printf(" ");
}
for (int j = 0; j < i+1; j++)
{
printf("#");
}
printf("\n");
}
}
在敲了我的头一段时间后，我发现了这个，并且它有效。
#include <stdio.h>
#include <cs50.h>
int main(void)
{
int height = 0;
int line = 0;
int column = 0;
while (true)
{
height = get_int("Height: ");
if (height >= 1 && height <= 8)
{
break;
}
}
/* Chooses a row: */
for ( line = 1 ; line <= height ; line++ )
{
/* Chooses a column: */
for ( column = 1 ; column <= height ; column++ )
{
/* Prints an hash character or a space character: */
if ( column >= height + 1 - line )
{
printf("#");
}
else
{
printf(" ");
}
}
printf("\n");
}
}
我使用 do-while 循环和 for 循环的组合解决了这个问题。一旦我有了金字塔的第一部分；我添加了另一个 for 循环来创建金字塔的第二部分。
#include <cs50.h>
#include <stdio.h>
int main(void)
{
int num_blocks;
int hashes;
int spaces;
do
{
//prompt user for input
num_blocks = get_int("Enter the number of blocks between (1 -8) inclusive: ");
//check user input
if (num_blocks > 8 || num_blocks <= 0)
{
num_blocks = get_int("Enter the number of blocks between (1 -8) inclusive: ");
}
}
//build mario game
while (num_blocks < 0);
for (int i = 0; i < num_blocks; i++)
{
// print out spaces
for (spaces = (num_blocks - i); spaces >= 2; spaces--)
{
printf(" ");
}
//loop to print out hashes
for (hashes = 0; hashes <= i; hashes++)
{
printf("#");
}
printf(" ");
//loop to print other hashes
for (hashes = 0; hashes <= i; hashes++)
{
printf("#");
}
printf("\n");
}
}
#include <stdio.h>
#include <cs50.h>
void print_row(int length);
void print_space(int space);
int main()
{
int column = get_int("What height pyramid do you want to make? : ");
for (int i = 0; i < column; i++)
{
print_space(column - i - 1); // Adjusted the space calculation
print_row(i + 1);
}
}
void print_row(int height)
{
for (int j = 0; j < height; j++)
{
printf("#");
}
printf("\n");
}
void print_space(int space)
{
for (int k = 0; k < space; k++)
{
printf(" ");
}
}
#include <stdio.h>
#include <cs50.h>
int main(void){
int s=0;
int hash=0;
int ht;
int h;
do{
printf("Height: ");
ht=GetInt();
for (h = ht; h > 0 ; h--){
printf("\n");
hash = ht - (h - 1);
s = ht - hash;
int i;
for (i = 0; i <= s; i++){
printf(" ");
}
for (i = 0; i <= hash; i++){
printf("#");
}
printf(" ");
for (i = 0; i <= hash; i++){
printf("#");
}
}
return 0;
}
while(ht > 0 || ht < 23);
return 0;
}
//this is how you only make the right aligned pyramid
#include <stdio.h>
#include <cs50.h>
int main(void){
int s=0;
int hash=0;
int ht;
int h;
do{
printf("Height: ");
ht=GetInt();
for (h = ht; h > 0 ; h--){
printf("\n");
hash = ht - (h - 1);
s = ht - hash;
int i;
for (i = 0; i <= s; i++){
printf(" ");
}
for (i = 0; i <= hash; i++){
printf("#");
}
}
return 0;
}
while(ht > 0 || ht < 23);
return 0;
}
//Author: Andriyevski Serhiy
#include <stdio.h>
#include <cs50.h>
int main(void)
{
// declaring my variables
int height;
int all_row;
int space;
int hash;
// prompts user for integer until integer is 0 to 23
do
{
printf("Please choose a number from 0 to 23:");
height = GetInt();
}
while ((height < 0) || (height > 23));
// this is the loop that will create the number of rows in the pyramid entered by the user
for (all_row = 1; all_row <= height; all_row++)
{
for (space = (height - all_row); space > 0; space--)
{
printf(" ");
}
for (hash = 1; hash <= (all_row + 1); hash++)
{
printf("#");
}
printf("\n");
}
return 0;
}
int main(void)
{
do
{
height = get_int("Height: "); //Requesting input from user for height.
}
while (height < 0 || height > 8); //Limits user input to between 0 and 8.
for (int rows = 1; rows <= height; rows++)
{
for (int spaces = 0; spaces < (height - rows); spaces++) //Based on the row number, there will be a certain amount of spaces. E.g. If the height is 8 and it is row 1, there are 7 spaces.
{
printf(" ");
}
for (int hashes = 0; hashes < rows; hashes++) //Based on which row it is, the number of hashes printed is equal to the row number. E.g. row 1 has 1 hash.
{
printf("#");
}
printf(" ");
for (int hashes = 0; hashes < rows; hashes++) //This prints the right side of the pyramid. No need to print the spaces.
{
printf("#");
}
printf("\n");
}
希望这段代码足够合理，易于阅读并希望它有所帮助！
此外，它还帮助我认识到终端从上到下打印，这是设计该问题算法的主要因素。