通过字符串循环

Question

我希望得到and这个词之后显示的所有单词。

var s = "you have a good day and time works for you and I'll make sure to 
get the kids together and that's why I was asking you to do the needful and 
confirm"

for (var  i= 0 ; i <= 3; i++){
    var body = s;
    var and = body.split("and ")[1].split(" ")[0];
    body = body.split("and ")[1].split(" ")[1];
    console.log(and);
}

我该怎么做呢？！

Answer 1

最简单的事情可能是使用正则表达式查找“​​和”后跟空格后面跟着“单词”，例如像/\band\s*([^\s]+)/g：

var s = "you have a good day and time works for you and I'll make sure to get the kids together and that's why I was asking you to do the needful and confirm";
var rex = /\band\s*([^\s]+)/g;
var match;
while ((match = rex.exec(s)) != null) {
  console.log(match[1]);
}

您可能需要稍微调整一下（例如，\b [“word boundary”]认为-是您可能不需要的边界;并且单独地，您对“word”的定义可能与[^\s]+等不同。）。

Answer 2

首先，您需要将整个字符串拆分为“和”，然后必须将给定数组的每个元素拆分为空格，第二个给定数组的第一个元素将是“和”字后面的第一个单词。

  var s = "you have a good day and time works for you and I'll make sure to get the kids together and that's why I was asking you to do the needful and confirm"


        var body = s;
        var and = body.split("and ");
        for(var i =0; i<and.length;i++){
        console.log(and[i].split(" ")[0]);
        }

Answer 3

您可以拆分，检查“和”字，并获得下一个：

var s = "you have a good day and time works for you and I'll make sure to get the kids together and that's why I was asking you to do the needful and confirm";
var a = s.split(' ');
var cont = 0;
var and = false;

while (cont < a.length) {
  if (and) {
    console.log(a[cont]);	
  }
  and = (a[cont] == 'and');
  cont++;
}

Answer 4

另一种使用replace的方法

var s = "you have a good day and time works for you and I'll make sure to get the kids together and that's why I was asking you to do the needful and confirm"

s.replace(/and\s+([^\s]+)/ig, (match, word) => console.log(word))