在同一个项目中使用.sa_sigaction和.sa_handler（手册页说明）

Question

在查看man page页面时，我在Linux手册页中偶然发现了一个令人困惑的注意事项：

在某些体系结构中涉及到一个联合：不要同时分配sa_handler和sa_sigaction（sigaction man page）。

有两种可能的方法来阅读它：

1. 这是否意味着，据我所知，你不允许在同一个.sa_sigaction中设置.sa_handler和struct sigaction。
2. 或者只允许在整个项目中使用.sa_sigaction或.sa_handler？

struct sigaction sigactionArray[SIGNAL_SIGACTION_ARRAY_SIZE] = {
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_handler = SIG_IGN, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_IGN, .sa_flags = SA_NODEFER},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_handler = SIG_IGN, .sa_flags = SA_NODEFER},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_IGN, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_IGN, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_IGN, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_IGN, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_handler = SIG_DFL, .sa_flags = SA_NODEFER},
   {.sa_sigaction = HandleBacktraceSignals, .sa_flags = SA_SIGINFO | SA_RESTART | SA_ONSTACK}
};

根据解释1.上面的代码很好，但是当定义2是正确的时候，因为我混合它将是无效的。

哪一个是真的？注意：在我的架构中，它被定义为联合

Answer 1

它只是谈论相同的结构。它解释了原因：它们可能是union的一部分，因此它们在结构中使用相同的内存。例如。它可能实际上是这样的：

struct sigaction {
    union {
        void     (*sa_handler)(int);
        void     (*sa_sigaction)(int, siginfo_t *, void *);
    },
    sigset_t   sa_mask;
    int        sa_flags;
    void     (*sa_restorer)(void);
};

因此，写入其中一个会覆盖另一个。