C＃json对象反序列化[关闭]

Question

我有一个JSON内容

[{
    "LocalObservationDateTime": "2018-04-23T08:10:00+05:00",
    "EpochTime": 1524453000,
    "WeatherText": "Sunny",
    "WeatherIcon": 1,
    "IsDayTime": true,
    "Temperature": {
        "Metric": {
            "Value": 29.6,
            "Unit": "C",
            "UnitType": 17
        },
        "Imperial": {
            "Value": 85.0,
            "Unit": "F",
            "UnitType": 18
        }
    },
    "MobileLink": "http://m.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us",
    "Link": "http://www.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us"
}]

我的班级处理这个内容如下：

class AccuWeather
{

    public class RootObject
    {
        public Class1[] Property1 { get; set; }
    }

    public class Class1
    {
        public DateTime LocalObservationDateTime { get; set; }
        public int EpochTime { get; set; }
        public string WeatherText { get; set; }
        public int WeatherIcon { get; set; }
        public bool IsDayTime { get; set; }
        public Temperature Temperature { get; set; }
        public string MobileLink { get; set; }
        public string Link { get; set; }
    }

我只是试图通过C＃中的以下代码片段反序列化此内容：

       private AccuWeather.RootObject Parse_A(string targetURI)
       {
        Uri uri = new Uri(targetURI);

        var webRequest = WebRequest.Create(uri);
        WebResponse response = webRequest.GetResponse();

        AccuWeather.RootObject wUData = null;

        try
        {
            using (var streamReader = new StreamReader(response.GetResponseStream()))
            {
                var responseData = streamReader.ReadToEnd();

                // if you want all the "raw data" as a string
                // just use: responseData.ToString()

                wUData = JsonConvert.DeserializeObject<AccuWeather.RootObject<Class1>>(responseData);
            }
        }
        catch (Exception e)
        {
            MessageBox.Show(e.Message);
        }

        return wUData;
    }//completed

我不确定这是反序列化JSON内容的正确有效方法。在这种情况下，任何人都能提供一些关于最佳实践的详细信息吗任何帮助都提前感谢！

Answer 1

您也可以使用.NET动态

var json = @"[{""LocalObservationDateTime"": ""2018-04-23T08:10:00+05:00"",
                ""EpochTime"": 1524453000,
                ""WeatherText"": ""Sunny"",
                ""WeatherIcon"": 1,
                ""IsDayTime"": true,
                ""Temperature"": {
                    ""Metric"": {
                        ""Value"": 29.6,
                        ""Unit"": ""C"",
                        ""UnitType"": 17
                    },
                    ""Imperial"": {
                        ""Value"": 85.0,
                        ""Unit"": ""F"",
                        ""UnitType"": 18
                    }
                },
                ""MobileLink"": ""http://m.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us"",
                ""Link"": ""http://www.accuweather.com/en/pk/jamaluddinwali/259991/current-weather/259991?lang=en-us""
            }]";

dynamic accuWeatherResp = JArray.Parse(json);
if (accuWeatherResp.Count == 0)
{
    Console.WriteLine("Response is Empty");
    return;
}
dynamic weather = accuWeatherResp[0];
if (weather != null)
{
    Console.WriteLine("Observation time: {0:s} Weather: {1}, Temperature: {2: 0.0} °C", weather.LocalObservationDateTime, weather.WeatherText, weather.Temperature.Metric.Value);
}

Answer 2

有一个名为quicktype.io的页面，您可以在其中粘贴JSON并接收C＃类和相应的转换器代码：

using System.Globalization;
using Newtonsoft.Json;
using Newtonsoft.Json.Converters;

public partial class Welcome
{
    [JsonProperty("LocalObservationDateTime")]
    public DateTimeOffset LocalObservationDateTime { get; set; }

    [JsonProperty("EpochTime")]
    public long EpochTime { get; set; }

    [JsonProperty("WeatherText")]
    public string WeatherText { get; set; }

    [JsonProperty("WeatherIcon")]
    public long WeatherIcon { get; set; }

    [JsonProperty("IsDayTime")]
    public bool IsDayTime { get; set; }

    [JsonProperty("Temperature")]
    public Temperature Temperature { get; set; }

    [JsonProperty("MobileLink")]
    public string MobileLink { get; set; }

    [JsonProperty("Link")]
    public string Link { get; set; }
}

public partial class Temperature
{
    [JsonProperty("Metric")]
    public Imperial Metric { get; set; }

    [JsonProperty("Imperial")]
    public Imperial Imperial { get; set; }
}

public partial class Imperial
{
    [JsonProperty("Value")]
    public double Value { get; set; }

    [JsonProperty("Unit")]
    public string Unit { get; set; }

    [JsonProperty("UnitType")]
    public long UnitType { get; set; }
}

public partial class Welcome
{
    public static Welcome[] FromJson(string json) => JsonConvert.DeserializeObject<Welcome[]>(json, QuickType.Converter.Settings);
}

public static class Serialize
{
    public static string ToJson(this Welcome[] self) => JsonConvert.SerializeObject(self, QuickType.Converter.Settings);
}

internal static class Converter
{
    public static readonly JsonSerializerSettings Settings = new JsonSerializerSettings
    {
        MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
        DateParseHandling = DateParseHandling.None,
        Converters = {
                new IsoDateTimeConverter { DateTimeStyles = DateTimeStyles.AssumeUniversal }
            },
    };
}