获得2张桌子
表1-ACTOR:ACTOR_ID,FIRST_NAME,LAST_NAME,LAST_UPDATE
表2-FILM_ACTOR:ACTOR_ID,FILM_ID,LAST_UPDATE
我尝试了以下方法来找出谁参加了最多的电影演出
select top 1 concat(ACTOR.FIRST_NAME, ACTOR.LAST_NAME) as Full_name
from ACTOR
left join FILM_ACTOR on ACTOR.ACTOR_ID = FILM_ACTOR.ACTOR_ID
group by FILM_ACTOR.ACTOR_ID
order by Full_name desc;
您可以进行聚合::
select a.*
from actor a
where a.actor_id = (select top (1) fm.actor_id
from film_actor fm
group by fm.actor_id
order by count(*) desc
);
我尝试了以下方法,以找出谁曾参加过最多的电影。
您的原始查询非常接近-您只需要适当的order by子句:
select top (1) concat(a.first_name, a.last_name) as full_name
from actor a
left join film_actor fa on a.actor_id = fa.actor_id
group by a.actor_id, a.first_name, a.last_name
order by count(*) desc;
如果要nth最忙的actor,则一种选择是使用窗口函数:
select full_name
from (
select concat(a.first_name, a.last_name) as full_name, row_number() over(order by count(*) desc) rn
from actor a
left join film_actor fa on a.actor_id = fa.actor_id
group by a.actor_id, a.first_name, a.last_name
) t
where rn = 3