尝试跟踪此功能，以便在程序运行 x 次后，会发生事情

Question

所以，我为我的项目制作了俄罗斯轮盘游戏。我变成了一个功能，现在我想要追踪。我想要前，150次后“枪”就会卡壳。我还想跟踪输出，以便我可以绘制图表，哪个数字出现最频繁等。下面的代码将被更改，以便它可以无限期地运行顺便说一句

myList = ["1", "2", "3", "4", "5", "6"] 随机导入 #洗牌列表，就像在左轮手枪上旋转鼓一样 随机播放（myList） 打印（我的列表）

#随机选择一个号码先拍 拍摄 = random.choice(myList) def RussianRoullete(shoot,myList): 触发拉力 = 0

while trigPull < 6:
    input("Press enter to pull the trigger")
#code below makes sure a chamber thats been "shot" wont be picked again!
    shoot1=random.randrange(len(myList))
    shoot2 = myList.pop(shoot1)
    #program runs this and it "shoots" the gun
    print("You pulled the trigger on chamber", shoot2)
    trigPull+=1

    if shoot2 == "6":
        print("BANG! Game over.")
        break
    else:
        print("Click... You survived this time.")
    
    

结果=俄罗斯轮盘（射击，myList） 打印（结果）

这是我到目前为止的代码，我真的对此一无所知，因为我对 python 有点陌生，对模型也绝对是新手！

Answer 1

编码花了足够长的时间。花点时间理解代码：

import random
game_count = 0
outcome_tracker = []
def russian_roulette():
    global game_count, outcome_tracker
    if game_count >= 150:
        print("The gun is jammed and it needs to be repaired! 😬")
        return "Jammed"
    myList = ["1", "2", "3", "4", "5", "6"]
    random.shuffle(myList)
    print("Chambers shuffled:", myList)
    trigPull = 0
    while trigPull < 6:
        input("Press enter to pull the trigger 🤠")
        if len(myList) == 0:
            print("All chambers are empty. Reloading... 😒")
            break
        shoot_index = random.randrange(len(myList))
        chamber_shot = myList.pop(shoot_index)
        print("You pulled the trigger on chamber", chamber_shot)
        trigPull += 1
        if chamber_shot == "6":
            print("BANG! Game over. 🤯")
            outcome_tracker.append((game_count + 1, int(chamber_shot)))
            break
        else:
            print("Click... You survived... for now at least. 😬")
    game_count += 1
    return chamber_shot
result = russian_roulette()
print("Result of this game:", result)

要跟踪多个游戏的结果，只需循环运行 Russian_roulette() 即可。