如何从数据库中获取记录并显示在 HTML 表格中

Question

这是我的表名 tbl_quotation_items:

qou_id	rfq_no	quo_desc	quo_supp	quo_total_cost
1	23-0003	键盘和鼠标	阿本森	6000
2	23-0003	P.E 管 3/4	阿本森	11050
3	23-0003	键盘和鼠标	艾森贸易	5400
4	23-0003	P.E 管 3/4	艾森贸易	12070

我期待在 HTML 表中有这样的输出：

rfq_no	quo_desc	阿本森	阿尔森交易
23-0003	键盘和鼠标	6000	5400
23-0003	P.E 管 3/4	11050	12070

我的代码只是从这个堆栈：

$query = "SELECT * FROM tbl_quotation_items WHERE rfq_no ='".$_POST['rfq_no']."'";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
$count = $statement->rowCount();
$output .= '
<table class="table">
  <thead>
    <TR>
        <TH>Article/Description</TH>
    </TR>
  <thead>';
if($count > 0)
{
   foreach($result as $row)
   {
     $output .= '
     <tr>
         <TD class="text-secondary" width="30%">
            '.$row["rfq_desc"].'
         </TD>
     </tr>';
   }
}
$output .='</table>';
echo $output;
$connect = null;

请帮忙！谢谢

Answer 1

你能试试下面的代码吗

<?php
// Establish a connection to the database
$servername = "localhost";
$username = "your_username";
$password = "your_password";
$dbname = "your_database_name";

$conn = mysqli_connect($servername, $username, $password, $dbname);

// Check if the connection is successful
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

// Fetch the records from the database
$sql = "SELECT * FROM tbl_quotation_items WHERE rfq_no = '23-0003'";
$result = mysqli_query($conn, $sql);

// Display the records in an HTML table
echo "<table>";
echo "<tr><th>rfq_no</th><th>quo_desc</th><th>Abenson</th><th>Alson Trading</th></tr>";
while ($row = mysqli_fetch_assoc($result)) {
    echo "<tr>";
    echo "<td>" . $row["rfq_no"] . "</td>";
    echo "<td>" . $row["quo_desc"] . "</td>";
    echo "<td>" . $row["Abenson"] . "</td>";
    echo "<td>" . $row["Alson Trading"] . "</td>";
    echo "</tr>";
}
echo "</table>";

// Close the database connection
mysqli_close($conn);
?>

如果您遇到任何问题，请告诉我