所以，我有一个出售水果的项目，我们目前正在使用术语“用于”我使用了其他术语，但是我们不能为此使用“ while”。
[如果客户想要一个苹果，则苹果可享受20％的折扣。如果他们想要折扣40％的香蕉，还有一个30折的橙]
它们都花了50比索在我停止程序之前，客户是无限的，最后，我必须加上我赚了多少钱的总和我知道我可以写“ IF”来获得分辨率，
但是我的问题是，我可以用什么来圈出问题？我可以用什么术语来将所有事物的总和加到最后？
根据您的发言，通过while循环可以做到这一点
fruit=input('what fruit are you selling?(banana,orange or apple) ')
count=int(input('how many? '))
fruits=['orange','apple','banana']
total=0
while fruit in fruits:
if fruit=='orange':
total=total+count*0.7*50
if fruit=='apple':
total=total+count*0.8*50
if fruit=='banana':
total=total+count*0.6*50
fruit=input('what fruit are you selling?(banana,orange or apple) ')
count=int(input('how many? '))
print(total,'Pesos')
我是否正确假设您希望不使用“ while”而是使用“ for”循环来解决此问题？这是一些不是很聪明的代码（如果您不按A B或C将会失败）：
apple = 50
apple_discount = 0.2
banana = 50
banana_discount = 0.3
orange = 50
orange_discount = 0.4
total_money = 0
for i in range(0, 2):
fruit = input("which fruit do you want (A), (B), (C)? ")
## chekc if input was A
if fruit == "A":
price = apple - apple * apple_discount
print("you bought an Apple for {} pesos".format(price))
## check if input was B
if fruit == "B":
price = banana - banana * banana_discount
print("you bought a Banana for {} pesos".format(price))
## check if input was C
if fruit == "C":
price = orange - orange * orange_discount
print("you bought an Orange for {} pesos".format(price))
total_money += price
print("total money to pay:", total_money)
## this makes the loop run one time longer every loop
## (which is stupid) so it runs forever:
i = i-1
我编写的代码尽可能地易于理解，希望它可以帮助您对此事产生更多的兴趣。