我有一个过滤谓词功能,用于过滤角度的mat-table
this.dataSource.filterPredicate = this.myService.tableFilter();
tableFilter(): (data: any, filter: string) => boolean {
let filterFunction = function (data, filter): boolean {
let filterValues = JSON.parse(filter);
... my logic ...
};
return filterFunction;
}
}
我想编写一个单元测试来测试此过滤器谓词功能
it('filter table', inject(
[MyService],
(service: MyService) => {
// how to do this?
let messageObject = service.tableFilter(dummyData,
getDummyFilterValues());
}
));
如何在单元测试中调用service.tableFilter函数?
在您的情况下,将以下代码中我返回对象的逻辑替换为布尔返回值。我认为问题在于如何调用返回的函数
打字稿代码
tableFilter(): (data: any, filter: string) => any {
const filterFunction = (data, filter) => {
const filterValues = JSON.parse(filter);
return data.find(d => {
return d.num === filterValues.num;
});
};
return filterFunction;
}
规格文件/单元测试块
it('test filterfx', () => {
const fixture = TestBed.createComponent(AppComponent);
const app = fixture.debugElement.componentInstance;
const filterfx = app.tableFilter();
expect(filterfx(app.data, JSON.stringify({ num: 'one' })).num).toEqual('one');
});