Bokeh-如何使用Select小部件更新滑块的最小值和最大值？

Question

[，请问如何通过用户选择小部件更新滑块的最小值和最大值，即index_min和index_max？例如，当选择u1时，滑块的最小值和最大值应为2586和2836。

import pandas as pd
from bokeh.layouts import column, layout
from bokeh.models import ColumnDataSource, Select, Slider
from bokeh.io import curdoc
from bokeh.plotting import figure

df = pd.DataFrame({'Time': [2586, 2836, 2986, 3269, 3702],
                   'X': [120, 210, 80, 98, 40],
                   'Y': [230, 40, 33, 122, 10],
                   'User': ['u1', 'u1', 'u2', 'u2', 'u2'],
                   'img': ['tree1.png', 'tree2.jpg', 'tree3.jpg', 'tree4.jpg','tree5.jpg']})

source = ColumnDataSource(data=dict(time=[], x=[], y=[], user=[], img=[]))

options = sorted(set(df['User']))
user_options = ['Please select ...'] + options
users = Select(title="User:", value=user_options[0], options=user_options)

index_min = df['Time'].min()
index_max = df['Time'].max()
index = Slider(start=index_min, end=index_max, value=index_max , step=1, title="Time Index")

def select_user():
    user_val = users.value
    selected = df[(df.Time <= index.value)]
    if (user_val != ""):
        selected = selected[selected.User.str.contains(user_val)==True]
    return selected

def update():
    dfnew = select_user()
    source.data = dict(time=dfnew['Time'], x=dfnew['X'], y=dfnew['Y'], user=dfnew['User'], img=dfnew['img'])


controls = [users, index]
for control in controls:
    control.on_change('value', lambda attr, old, new: update())


p = figure(plot_width = 600, plot_height = 600)
p.circle(x="x", y="y", source=source, legend='user')


update() # initial load of the data

l = layout(column(users, index, p))

curdoc().add_root(l)
    

[，请问如何通过用户选择小部件更新滑块的最小值和最大值，即index_min和index_max？例如，当选择u1时，滑块的最小值和最大值应为2586 ...

Answer 1

这就是我的做法。