我有一个如下的numpy数组atoms.numbers
:
array([27, 27, 27, 27, 27, 27, 57, 57, 57, 57, 57, 57, 57, 57, 27, 27, 8,
8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8,
8, 8, 8, 8, 8, 8, 27, 27, 27, 27, 27, 27, 57, 57, 57, 57, 57,
57, 57, 57, 27, 27, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8])
我可以使用以下命令替换所有相同的实例,例如数组中的每个“ 57”:
atoms.numbers[atoms.numbers==57]=38
给出:
array([27, 27, 27, 27, 27, 27, 38, 38, 38, 38, 38, 38, 38, 38, 27, 27, 8,
8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8,
8, 8, 8, 8, 8, 8, 27, 27, 27, 27, 27, 27, 38, 38, 38, 38, 38,
38, 38, 38, 27, 27, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8])
我希望能够替换数组中的每个第n个实例。我尝试过:
n=5
atoms.numbers[atoms.numbers==57][::n]=38
这不起作用。
使用np.where
查找感兴趣项目的索引。查找每个第n个索引。更新项目:
locations = np.where(numbers == 57)[0]
numbers[locations[::n]] = 38