与this question类似,我想使用我自己的用户定义类型“AccountNumber”执行SQL“like”操作。
QueryDSL Entity类定义列的字段如下所示:
public final SimplePath<com.myorg.types.AccountNumber> accountNumber;
我已尝试使用以下代码在SQL中实现“like”操作,但在运行查询之前比较类型时会出现错误:
final Path path=QBusinessEvent.businessEvent.accountNumber;
final Expression<AccountNumber> constant = Expressions.constant(AccountNumber.valueOfWithWildcard(pRegion.toString()));
final BooleanExpression booleanOperation = Expressions.booleanOperation(Ops.STARTS_WITH, path, constant);
expressionBuilder.and(booleanOperation);
错误是:
org.springframework.dao.InvalidDataAccessApiUsageException: Parameter value [7!%%] did not match expected type [com.myorg.types.AccountNumber (n/a)]
有没有人能够使用QueryDSL / JPA组合实现这一目标?
您是否尝试使用String常量?
Path<?> path = QBusinessEvent.businessEvent.accountNumber;
Expression<String> constant = Expressions.constant(pRegion.toString());
Predicate predicate = Expressions.predicate(Ops.STARTS_WITH, path, constant);
最后,我的同事给了我一个小费来做以下事情:
if (pRegion != null) {
expressionBuilder.and(Expressions.booleanTemplate("{0} like concat({1}, '%')", qBusinessEvent.accountNumber, pRegion));
}
这似乎可以解决问题!
好像有bug /含糊不清。就我而言,我需要搜索不同类型的几个字段(String
,Number
),例如SQL看起来像:
SELECT * FROM table AS t WHERE t.name = "%some%" OR t.id = "%some%";
我的代码看起来像:
BooleanBuilder where = _getDefaultPredicateBuilder();
BooleanBuilder whereLike = new BooleanBuilder();
for(String likeField: _likeFields){
whereLike = whereLike.or(_pathBuilder.getString(likeField).contains(likeValue));
}
where.and(whereLike);
如果第一个_likeFields
是String
的类型 - 请求工作正常,否则它抛出异常。