我正在使用System.Xml.Serialization中的XmlSerializer
。
我有一个列表(或两个列表),以xsi:type
分隔。
<?xml version="1.0" encoding="utf-8"?>
<ButikerOmbud xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Info>
<Meddelande>blah blah</Meddelande>
</Info>
<ButikOmbud xsi:type="StoreAssortmentViewModel">
<Typ>Butik</Typ><Nr>2515</Nr>
</ButikOmbud>
<ButikOmbud xsi:type="StoreAssortmentViewModel">
<Typ>Butik</Typ><Nr>2516</Nr>
</ButikOmbud>
<ButikOmbud xsi:type="AgentAssortmentViewModel">
<Typ>Ombud</Typ><Nr>011703-91A</Nr>
</ButikOmbud>
<ButikOmbud xsi:type="AgentAssortmentViewModel">
<Typ>Ombud</Typ><Nr>011703-92B</Nr>
</ButikOmbud>
</ButikerOmbud>
我创建了一些映射到此的类:
[XmlRoot(ElementName = "ButikerOmbud")]
public class ButiksCollection
{
[XmlElement(ElementName = "Info")]
public Info Info { get; set; }
[XmlElement(ElementName = "ButikOmbud")]
public List<Butik> Butiker { get; set; }
}
[XmlRoot(ElementName = "ButikOmbud")]
[XmlType(TypeName = "StoreAssortmentViewModel")]
public class Butik
{
[XmlElement(ElementName = "Typ")]
public string Typ { get; set; }
[XmlElement(ElementName = "Nr")]
public int Nr { get; set; }
}
然后我会做的
(ButiksCollection)(new XmlSerializer(typeof(ButiksCollection)).Deserialize(memoryStream));
如果仅存在StoreAssortmentViewModel
,这应该起作用。但是,鉴于在同一节点下存在AgentAssortmentViewModel
。我不确定该如何反序列化。我假设List<Butik> Agents
上应该有另一个集合ButiksCollection
。
我发现的似乎唯一映射到xsi:type
的属性应用于类,我认为这不是我想要的]
我如何安排和分配我的课程,这样可以取消序列化?
尝试以下内容:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Serialization;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = @"c:\temp\test.xml";
static void Main(string[] args)
{
XmlReader reader = XmlReader.Create(FILENAME);
XmlSerializer serializer = new XmlSerializer(typeof(ButiksCollection));
ButiksCollection butik = (ButiksCollection)serializer.Deserialize(reader);
}
}
[XmlRoot(ElementName = "ButikerOmbud")]
public class ButiksCollection
{
[XmlElement(ElementName = "Info")]
public Info Info { get; set; }
[XmlElement(ElementName = "ButikOmbud")]
public List<Butik> Butiker { get; set; }
}
[XmlRoot(ElementName = "ButikOmbud")]
[XmlInclude(typeof(StoreAssortmentViewModel))]
[XmlInclude(typeof(AgentAssortmentViewModel))]
public class Butik
{
[XmlElement(ElementName = "Typ")]
public string Typ { get; set; }
[XmlElement(ElementName = "Nr")]
public string Nr { get; set; }
}
public class Info
{
public string Meddelande { get; set; }
}
public class StoreAssortmentViewModel : Butik
{
}
public class AgentAssortmentViewModel : Butik
{
}
}