如何检查Android上的互联网访问? InetAddress永远不会超时

问题描述 投票:612回答:50

我有一个AsyncTask应该检查网络访问主机名。但doInBackground()永远不会超时。有人有线索吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}
android networking asynchronous
50个回答
483
投票

Network connection / Internet access

  • isConnectedOrConnecting()(在大多数答案中使用)检查任何网络连接
  • 要了解这些网络中是否有任何网络访问,请使用以下方法之一

A) Ping a Server (easy)

// ICMP 
public boolean isOnline() {
    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int     exitValue = ipProcess.waitFor();
        return (exitValue == 0);
    }
    catch (IOException e)          { e.printStackTrace(); }
    catch (InterruptedException e) { e.printStackTrace(); }

    return false;
}

+可以在主线上运行

-不适用于某些旧设备(Galays S3等),如果没有可用的互联网,它会阻塞一段时间。

B) Connect to a Socket on the Internet (advanced)

// TCP/HTTP/DNS (depending on the port, 53=DNS, 80=HTTP, etc.)
public boolean isOnline() {
    try {
        int timeoutMs = 1500;
        Socket sock = new Socket();
        SocketAddress sockaddr = new InetSocketAddress("8.8.8.8", 53);

        sock.connect(sockaddr, timeoutMs);
        sock.close();

        return true;
    } catch (IOException e) { return false; }
}

+非常快(无论哪种方式),适用于所有设备,非常可靠

-无法在UI线程上运行

这在每台设备上都非常可靠,而且速度非常快。它需要在一个单独的任务中运行(例如ScheduledExecutorServiceAsyncTask)。

Possible Questions

  • 真的够快吗? 是的,非常快;-)
  • 没有可靠的方法来检查互联网,除了在互联网上测试一些东西? 不是我所知,但请告诉我,我会编辑我的答案。
  • 如果DNS关闭怎么办? Google DNS(例如8.8.8.8)是全球最大的公共DNS。截至2013年,它每天为1300亿个请求提供服务。我们只是说,你的应用可能不是当天的话题。
  • 需要哪些权限? <uses-permission android:name="android.permission.INTERNET" /> 只是互联网访问 - 惊喜^^(顺便说一句,你有没有想过,如果没有这个许可,这里建议的一些方法甚至可能有一个关于互联网访问的远程胶水?)

Extra: One-shot AsyncTask Example

class InternetCheck extends AsyncTask<Void,Void,Boolean> {

    private Consumer mConsumer;
    public  interface Consumer { void accept(Boolean internet); }

    public  InternetCheck(Consumer consumer) { mConsumer = consumer; execute(); }

    @Override protected Boolean doInBackground(Void... voids) { try {
        Socket sock = new Socket();
        sock.connect(new InetSocketAddress("8.8.8.8", 53), 1500);
        sock.close();
        return true;
    } catch (IOException e) { return false; } }

    @Override protected void onPostExecute(Boolean internet) { mConsumer.accept(internet); }
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    new InternetCheck(internet -> { /* do something with boolean response */ });

Extra: One-shot RxJava/RxAndroid Example (Kotlin)

fun hasInternetConnection(): Single<Boolean> {
  return Single.fromCallable {
    try {
      // Connect to Google DNS to check for connection
      val timeoutMs = 1500
      val socket = Socket()
      val socketAddress = InetSocketAddress("8.8.8.8", 53)

      socket.connect(socketAddress, timeoutMs)
      socket.close()

      true
    } catch (e: IOException) {
      false
    }
  }
  .subscribeOn(Schedulers.io())
  .observeOn(AndroidSchedulers.mainThread())
}

///////////////////////////////////////////////////////////////////////////////////
    // Usage

    hasInternetConnection().subscribe { hasInternet -> /* do something */}

9
投票

这不止一种方式

首先,最短但效率低的方式

仅需要网络状态权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

那么这个方法,

 public boolean activeNetwork () {
        ConnectivityManager cm =
                (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE);

        NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
        boolean isConnected = activeNetwork != null &&
                activeNetwork.isConnected();

        return isConnected;

    }

正如答案中所见ConnectivityManager是一个解决方案,我只是在一个方法中添加它,这是一个简单的方法都使用 如果网络访问不是因特网访问,ConnectivityManager返回true,意味着如果您的WiFi连接到路由器但路由器没有互联网它返回true,它会检查连接可用性

第二,有效的方式

需要网络状态和Internet权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.INTERNET" />

然后这节课,

 public class CheckInternetAsyncTask extends AsyncTask<Void, Integer, Boolean> {

        private Context context;

        public CheckInternetAsyncTask(Context context) {
            this.context = context;
        }

        @Override
        protected Boolean doInBackground(Void... params) {

            ConnectivityManager cm =
                    (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);

            assert cm != null;
            NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
            boolean isConnected = activeNetwork != null &&
                    activeNetwork.isConnected();


            if (isConnected) {
                try {
                    HttpURLConnection urlc = (HttpURLConnection)
                            (new URL("http://clients3.google.com/generate_204")
                                    .openConnection());
                    urlc.setRequestProperty("User-Agent", "Android");
                    urlc.setRequestProperty("Connection", "close");
                    urlc.setConnectTimeout(1500);
                    urlc.connect();
                    if (urlc.getResponseCode() == 204 &&
                            urlc.getContentLength() == 0)
                        return true;

                } catch (IOException e) {
                    Log.e("TAG", "Error checking internet connection", e);
                    return false;
                }
            } else {
                Log.d("TAG", "No network available!");
                return false;
            }


            return null;
        }

        @Override
        protected void onPostExecute(Boolean result) {
            super.onPostExecute(result);
            Log.d("TAG", "result" + result);

            if(result){
                // do ur code
            }

        }


    }

打电话给CheckInternetAsyncTask

new CheckInternetAsyncTask(getApplicationContext()).execute();

一些解释: -

  • 你必须检查AsyncTask上的互联网,否则它可以在某些情况下扔android.os.NetworkOnMainThreadException
  • 如果true发送请求,ConnectivityManager用于检查网络访问(Ping)
  • 请求发送到http://clients3.google.com/generate_204,已知这个众所周知的URL返回一个HTTP状态为204的空页面,这比http://www.google.com更快更有效,读取this。如果你有网站,只有你在应用程序中使用它,首选你的网站而不是谷歌
  • 超时可以改变范围(20ms - > 2000ms),常用1500ms

8
投票

到目前为止,我所看到的最短和最干净的方式应该是:

public final static boolean isConnected( Context context )
{   
   final ConnectivityManager connectivityManager = 
         (ConnectivityManager) context.getSystemService( Context.CONNECTIVITY_SERVICE );  
   final NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();    
   return networkInfo != null && networkInfo.isConnected();
}

PS:这不会ping任何主机,它只是检查connectionstatus,所以如果您的路由器没有互联网连接并且您的设备已连接到它,这种方法将返回true,尽管您没有互联网。 对于实际测试,我建议执行HttpHead请求(例如,到www.google.com)并检查状态,如果200 OK,一切正常并且您的设备有互联网连接。


8
投票

这是我使用的方法:

public boolean isNetworkAvailable(final Context context) {
    return ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE)).getActiveNetworkInfo() != null;
}

更好的是,检查以确保它“连接”:

public boolean isNetworkAvailable(final Context context) {
    final ConnectivityManager connectivityManager = ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE));
    return connectivityManager.getActiveNetworkInfo() != null && connectivityManager.getActiveNetworkInfo().isConnected();
}

以下是如何使用该方法:

if (isNetworkAvailable(context)) {
    // code here
} else {
    // code
}

需要许可:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

https://stackoverflow.com/a/16124915/950427


7
投票

移动设备上的一个重要用例是确保存在实际连接。当移动用户进入具有“强制门户”的Wifi网络时,这是一个常见问题,他们需要登录。我在后台使用此阻止功能以确保存在连接。

/*
 * Not Thread safe. Blocking thread. Returns true if it
 * can connect to URL, false and exception is logged.
 */
public boolean checkConnectionHttps(String url){
    boolean responded = false;
    HttpGet requestTest = new HttpGet(url);
    HttpParams params = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(params, 3000);
    HttpConnectionParams.setSoTimeout(params, 5000);
    DefaultHttpClient client = new DefaultHttpClient(params);
    try {
        client.execute(requestTest);
        responded = true;
    } catch (ClientProtocolException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
    } catch (IOException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
        e.printStackTrace();
    }
    return responded;
}

6
投票

您可以遍历所有网络连接并检查是否至少有一个可用连接:

public boolean isConnected() {
    boolean connected = false;

    ConnectivityManager cm = 
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

    if (cm != null) {
        NetworkInfo[] netInfo = cm.getAllNetworkInfo();

        for (NetworkInfo ni : netInfo) {
            if ((ni.getTypeName().equalsIgnoreCase("WIFI")
                    || ni.getTypeName().equalsIgnoreCase("MOBILE"))
                    && ni.isConnected() && ni.isAvailable()) {
                connected = true;
            }

        }
    }

    return connected;
}

6
投票

对我来说,检查Activity类中的连接状态不是一个好习惯,因为

ConnectivityManager cm =
    (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

应该在那里调用,或者你需要将你的Activity实例(上下文)下推到连接处理程序类,以便能够检查那里的连接状态当没有可用的连接(wifi,网络)时,我捕获了UnknownHostException异常:

JSONObject jObj = null;
Boolean responded = false;
HttpGet requestForTest = new HttpGet("http://myserver.com");
try {
    new DefaultHttpClient().execute(requestForTest);
    responded = true;
} catch (UnknownHostException e) {
    jObj = new JSONObject();
    try {
        jObj.put("answer_code", 1);
        jObj.put("answer_text", "No available connection");
    } catch (Exception e1) {}
    return jObj;
} catch (IOException e) {
    e.printStackTrace();
}

通过这种方式,我可以处理这种情况以及同一类中的其他情况(我的服务器总是以json字符串回复)


6
投票

它对我有用。试试看。

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    try {
        URL url = new URL("http://stackoverflow.com/posts/11642475/edit" );
        //URL url = new URL("http://www.nofoundwebsite.com/" );
        executeReq(url);
        Toast.makeText(getApplicationContext(), "Webpage is available!", Toast.LENGTH_SHORT).show();
    }
    catch(Exception e) {
        Toast.makeText(getApplicationContext(), "oops! webpage is not available!", Toast.LENGTH_SHORT).show();
    }
}

private void executeReq(URL urlObject) throws IOException
{
    HttpURLConnection conn = null;
    conn = (HttpURLConnection) urlObject.openConnection();
    conn.setReadTimeout(30000);//milliseconds
    conn.setConnectTimeout(3500);//milliseconds
    conn.setRequestMethod("GET");
    conn.setDoInput(true);

    // Start connect
    conn.connect();
    InputStream response =conn.getInputStream();
    Log.d("Response:", response.toString());
}}

5
投票

我使用此代码而不是InetAddress:

    try {

        URL url = new URL("http://"+params[0]);

        HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
        urlc.setRequestProperty("User-Agent", "Android Application:"+Z.APP_VERSION);
        urlc.setRequestProperty("Connection", "close");
        urlc.setConnectTimeout(1000 * 30); // mTimeout is in seconds
        urlc.connect();
        if (urlc.getResponseCode() == 200) {
            Main.Log("getResponseCode == 200");
            return new Boolean(true);
        }
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

5
投票

检查Android网络/互联网连接状态并不复杂。以下DetectConnection课程将帮助您检查此状态:

import android.content.Context;
import android.net.ConnectivityManager;

public class DetectConnection {
    public static boolean checkInternetConnection(Context context) {
        ConnectivityManager con_manager = (ConnectivityManager) context
                                .getSystemService(Context.CONNECTIVITY_SERVICE);

        if (con_manager.getActiveNetworkInfo() != null
            && con_manager.getActiveNetworkInfo().isAvailable()
            && con_manager.getActiveNetworkInfo().isConnected()) {
                return true;
        } else {
            return false;
        }
    }
}

欲了解更多详情,请访问How to Check Android Network / Internet Connectivity Status


5
投票

最佳方法:

public static boolean isOnline() {
    try {
    InetAddress.getByName("google.com").isReachable(3);

    return true;
    } catch (UnknownHostException e){
    return false;
    } catch (IOException e){
    return false;
    }
    }

1019
投票

如果设备处于飞行模式(或者可能是在没有可用网络的其他情况下),cm.getActiveNetworkInfo()将是null,因此您需要添加null检查。

修改后的(Eddie's solution):

public boolean isOnline() {
    ConnectivityManager cm =
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    return netInfo != null && netInfo.isConnectedOrConnecting();
}

还要向AndroidManifest.xml添加以下权限:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

另一个小问题,如果你在给定的时间点绝对需要网络连接,那么使用netInfo.isConnected()而不是netInfo.isConnectedOrConnecting可能会更好。我想这取决于个人用例。


5
投票

以下是我的Utils类的代码:

public static boolean isNetworkAvailable(Context context) {
        ConnectivityManager connectivityManager 
              = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
        return activeNetworkInfo != null && activeNetworkInfo.isConnected();
}

5
投票
public class Network {

Context context;

public Network(Context context){
    this.context = context;
}

public boolean isOnline() {
    ConnectivityManager cm =
            (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);

    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    return activeNetwork != null &&
                          activeNetwork.isConnectedOrConnecting();
}

}

5
投票

您可以使用此方法检测网络可用性 -

public static boolean isDeviceOnline(Context context) {
        boolean isConnectionAvail = false;
        try {
            ConnectivityManager cm = (ConnectivityManager) context
                    .getSystemService(Context.CONNECTIVITY_SERVICE);
            NetworkInfo netInfo = cm.getActiveNetworkInfo();
            return netInfo.isConnected();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return isConnectionAvail;
    }

5
投票

此方法为您提供了一种非常快速的方法(用于实时反馈)或更慢的方法(用于需要可靠性的一次性检查)的选项

public boolean isNetworkAvailable(bool SlowButMoreReliable) {
    bool Result = false; 
    try {
        if(SlowButMoreReliable){
            ConnectivityManager MyConnectivityManager = null;
            MyConnectivityManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

            NetworkInfo MyNetworkInfo = null;
            MyNetworkInfo = MyConnectivityManager.getActiveNetworkInfo();

            Result = MyNetworkInfo != null && MyNetworkInfo.isConnected();

        } else
        {
            Runtime runtime = Runtime.getRuntime();
            Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");

            int i = ipProcess.waitFor();

            Result = i== 0;

        }

    } catch(Exception ex)
    {
        //Common.Exception(ex); //This method is one you should have that displays exceptions in your log
    }
    return Result;
}

5
投票

我已经应用了@Levit提供的解决方案并创建了不会调用额外Http请求的函数。

它将解决错误Unable to Resolve Host

public static boolean isInternetAvailable(Context context) {
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork == null) return false;

    switch (activeNetwork.getType()) {
        case ConnectivityManager.TYPE_WIFI:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        case ConnectivityManager.TYPE_MOBILE:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        default:
            return false;
    }
    return false;
}

private static boolean isInternet() {

    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int exitValue = ipProcess.waitFor();
        Debug.i(exitValue + "");
        return (exitValue == 0);
    } catch (IOException | InterruptedException e) {
        e.printStackTrace();
    }

    return false;
}

现在称之为,

if (!isInternetAvailable(getActivity())) {
     //Show message
} else {
     //Perfoem the api request
}

4
投票

使用ConnectivityManager的其他答案是错误的,因为拥有网络连接并不意味着您可以访问Internet。例如,用户可能连接到咖啡店的WiFi门户但无法访问互联网。要检查互联网是否可访问,您必须尝试连接到实际的服务器。通常,当您要执行此操作时,您需要记住要连接的特定服务器,因此请检查您是否可以连接到该服务器。这是检查服务器连接的简单方法。

private boolean isOnTheInternet() {
    try {
        URLConnection urlConnection = new URL("http://yourserver").openConnection();
        urlConnection.setConnectTimeout(400);
        urlConnection.connect();
        return true;
    } catch (Exception e) {
        return false;
    }
}

设置ConnectTimeout的原因是,否则它默认为TCP超时,可以持续很长时间。

另请注意,Android不允许您在主线程上运行此操作。



4
投票

我已经完成了所有的答案,我想出了自己的答案,首先检查互联网是否可用,如果互联网可用,那么它会检查它是否有效。

我已经包含了所有必要的方法和类来检查活动的Internet连接。

NetworkUtils.class

public class NetworkUtils {

    public static final int STATUS_CONNECTED = 0 ;

    public static boolean isInternetAvailable(Context ctx){
        ConnectivityManager cm = (ConnectivityManager)ctx.getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
        return activeNetwork != null && activeNetwork.isConnectedOrConnecting();
    }

    public static int isInternetActiveWithPing() {
        try {
            Runtime runtime = Runtime.getRuntime();
            Process process = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
            int exitValue = process.waitFor();
            return exitValue;
        } catch (Exception ex) {
            return -1;
        }
    }

    public static boolean isInternetActiveWithInetAddress() {
        try {
            InetAddress inetAddress = InetAddress.getByName("www.google.com");
            return inetAddress != null && !inetAddress.toString().equals("");
        } catch (Exception ex) {
            return false;
        }
    }

    public static void displayInternetConnectionMessage(Context ctx){
        Toast.makeText(ctx, "Check Internet Connection", Toast.LENGTH_SHORT).show();
    }
}

您可以使用以下代码检查Internet是否处于活动状态:

 private void checkInternetConnection() {
        if (NetworkUtils.isInternetAvailable(this)) {
            new Thread(new Runnable() {
                @Override
                public void run() {
                    if (NetworkUtils.isInternetActiveWithPing() == NetworkUtils.STATUS_CONNECTED) {
                        performNetworkingOperations();
                    } else {
                        if (NetworkUtils.isInternetActiveWithInetAddress()) {
                            performNetworkingOperations();
                        } else {
                            displayConnectionMessage();
                        }
                    }
                }
            }).start();

        } else {
            displayConnectionMessage();
        }
    }

    private void performNetworkingOperations() {
        runOnUiThread(new Runnable() {
            @Override
            public void run() {
                Toast.makeText(MainActivity.this, "Internet is Available", Toast.LENGTH_SHORT).show();
            }
        });
    }

    private void displayConnectionMessage() {
        runOnUiThread(new Runnable() {
            @Override
            public void run() {
                NetworkUtils.displayInternetConnectionMessage(MainActivity.this);
            }
        });
    }

4
投票

检查我们是否与isAvailable()连接以及是否可以与isConnected()建立连接非常重要

private static ConnectivityManager manager;

public static boolean isOnline(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.isAvailable() && networkInfo.isConnected();
}

你可以确定网络活跃WiFi的类型:

public static boolean isConnectedWifi(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.getType() == ConnectivityManager.TYPE_WIFI;
}

或移动Móvil

public static boolean isConnectedMobile(Context context) {
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
    return networkInfo != null && networkInfo.getType() == ConnectivityManager.TYPE_MOBILE;
}

不要忘记权限:

    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
   <uses-permission android:name="android.permission.INTERNET" />

3
投票

只需创建以下检查Internet连接的类:

public class ConnectionStatus {

    private Context _context;

    public ConnectionStatus(Context context) {
        this._context = context;
    }

    public boolean isConnectionAvailable() {
        ConnectivityManager connectivity = (ConnectivityManager) _context
                .getSystemService(Context.CONNECTIVITY_SERVICE);
        if (connectivity != null) {
            NetworkInfo[] info = connectivity.getAllNetworkInfo();
            if (info != null)
                for (int i = 0; i < info.length; i++)
                    if (info[i].getState() == NetworkInfo.State.CONNECTED) {
                        return true;
                    }
        }
        return false;
    }
}

该类只包含一个返回连接状态的布尔值的方法。因此,简单来说,如果方法找到与Internet的有效连接,则返回值为true,否则为false,如果未找到有效连接。

然后,MainActivity中的以下方法从前面描述的方法调用结果,并提示用户采取相应的操作:

public void addListenerOnWifiButton() {
        Button btnWifi = (Button)findViewById(R.id.btnWifi);

        iia = new ConnectionStatus(getApplicationContext());

        isConnected = iia.isConnectionAvailable();
        if (!isConnected) {
            btnWifi.setOnClickListener(new View.OnClickListener() {

                @Override
                public void onClick(View v) {
                    startActivity(new Intent(Settings.ACTION_WIFI_SETTINGS));
                    Toast.makeText(getBaseContext(), "Please connect to a hotspot",
                            Toast.LENGTH_SHORT).show();
                }
            });
        }
        else {
            btnWifi.setVisibility(4);
            warning.setText("This app may use your mobile data to update events and get their details.");
        }
    }

在上面的代码中,如果结果为false,(因此没有互联网连接,用户将被带到Android wi-fi面板,在那里他被提示连接到Wi-Fi热点。


293
投票

不需要复杂。最简单的框架方式是使用ACCESS_NETWORK_STATE权限并只创建一个连接的方法

public boolean isOnline() {
    ConnectivityManager cm =
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

    return cm.getActiveNetworkInfo() != null && 
       cm.getActiveNetworkInfo().isConnectedOrConnecting();
}

如果您有特定的主机和连接类型(wifi /移动),您也可以使用requestRouteToHost

您还需要:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

在你的Android清单中。


3
投票

更新29/06/2015如果您正在使用Xamarin.Android并想要检查连接性,则可以使用Nuget包在多个平台上为您提供此功能。好的候选人是herehere。 [更新完]

上面的答案非常好,但它们都是Java,几乎所有的都检查连接。就我而言,我需要与特定类型的连接建立连接,而我正在开发Xamarin.Android。而且,我没有在硬件层传递对我的活动Context的引用,我使用了Application Context。所以这是我的解决方案,以防有人来这里有类似的要求。我还没有完成全部测试,一旦完成测试就会更新答案

using Android.App;
using Android.Content;
using Android.Net;

namespace Leopard.Mobile.Hal.Android
{
    public class AndroidNetworkHelper
    {
        public static AndroidNetworkStatus GetWifiConnectivityStatus()
        {
            return GetConnectivityStatus(ConnectivityType.Wifi);
        }

        public static AndroidNetworkStatus GetMobileConnectivityStatus()
        {
            return GetConnectivityStatus(ConnectivityType.Mobile);
        }

        #region Implementation

        private static AndroidNetworkStatus GetConnectivityStatus(ConnectivityType connectivityType)
        {
            var connectivityManager = (ConnectivityManager)Application.Context.GetSystemService(Context.ConnectivityService);
            var wifiNetworkInfo = connectivityManager.GetNetworkInfo(connectivityType);
            var result = GetNetworkStatus(wifiNetworkInfo);
            return result;
        }

        private static AndroidNetworkStatus GetNetworkStatus(NetworkInfo wifiNetworkInfo)
        {
            var result = AndroidNetworkStatus.Unknown;
            if (wifiNetworkInfo != null)
            {
                if (wifiNetworkInfo.IsAvailable && wifiNetworkInfo.IsConnected)
                {
                    result = AndroidNetworkStatus.Connected;
                }
                else
                {
                    result = AndroidNetworkStatus.Disconnected;
                }
            }
            return result;
        } 

        #endregion
    }

    public enum AndroidNetworkStatus
    {
        Connected,
        Disconnected,
        Unknown
    }

63
投票

要使getActiveNetworkInfo()工作,您需要将以下内容添加到清单中。

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

46
投票

检查这段代码......它对我有用:)

public static void isNetworkAvailable(final Handler handler, final int timeout) {
    // ask fo message '0' (not connected) or '1' (connected) on 'handler'
    // the answer must be send before before within the 'timeout' (in milliseconds)

    new Thread() {
        private boolean responded = false;   
        @Override
        public void run() { 
            // set 'responded' to TRUE if is able to connect with google mobile (responds fast) 
            new Thread() {      
                @Override
                public void run() {
                    HttpGet requestForTest = new HttpGet("http://m.google.com");
                    try {
                        new DefaultHttpClient().execute(requestForTest); // can last...
                        responded = true;
                    } 
                    catch (Exception e) {
                    }
                } 
            }.start();

            try {
                int waited = 0;
                while(!responded && (waited < timeout)) {
                    sleep(100);
                    if(!responded ) { 
                        waited += 100;
                    }
                }
            } 
            catch(InterruptedException e) {} // do nothing 
            finally { 
                if (!responded) { handler.sendEmptyMessage(0); } 
                else { handler.sendEmptyMessage(1); }
            }
        }
    }.start();
}

然后,我定义处理程序:

Handler h = new Handler() {
    @Override
    public void handleMessage(Message msg) {

        if (msg.what != 1) { // code if not connected

        } else { // code if connected

        }   
    }
};

...并启动测试:

isNetworkAvailable(h,2000); // get the answser within 2000 ms

45
投票

看一下ConnectivityManager类。您可以使用此类来获取有关主机上活动连接的信息。 http://developer.android.com/reference/android/net/ConnectivityManager.html

编辑:你可以使用

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .getNetworkInfo(ConnectivityManager.TYPE_MOBILE) 

要么

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .getNetworkInfo(ConnectivityManager.TYPE_WIFI) 

并解析返回的NetworkInfo对象的DetailedState枚举

编辑编辑:要了解您是否可以访问主机,您可以使用

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .requestRouteToHost(TYPE_WIFI, int hostAddress)

显然,我使用Context.getSystemService(Context.CONNECTIVITY_SERVICE)作为代理来说

ConnectivityManager cm = Context.getSystemService(Context.CONNECTIVITY_SERVICE);
cm.yourMethodCallHere();

26
投票

在这个link找到并修改(!):

在您的清单文件中至少添加:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

如果您正在访问它,您可能已经拥有INTERNET权限。然后,允许测试连接的布尔函数是:

private boolean checkInternetConnection() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    // test for connection
    if (cm.getActiveNetworkInfo() != null
            && cm.getActiveNetworkInfo().isAvailable()
            && cm.getActiveNetworkInfo().isConnected()) {
        return true;
    } else {
        Log.v(TAG, "Internet Connection Not Present");
        return false;
    }
}

15
投票

我做了这个代码,它是最简单的,它只是一个布尔值。通过问if(isOnline()){

如果有连接并且它可以连接到页面状态代码200(稳定连接),则会得到。

确保添加正确的INTERNETACCESS_NETWORK_STATE权限。

public boolean isOnline() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    if (netInfo != null && netInfo.isConnected()) {
        try {
            URL url = new URL("http://www.google.com");
            HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
            urlc.setConnectTimeout(3000);
            urlc.connect();
            if (urlc.getResponseCode() == 200) {
                return new Boolean(true);
            }
        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
    return false;
}

12
投票

它对我有用:

要验证网络可用性:

private Boolean isNetworkAvailable() {
ConnectivityManager connectivityManager 
      = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
return activeNetworkInfo != null && activeNetworkInfo.isConnectedOrConnecting();}

验证互联网访问:

public Boolean isOnline() {
    try {
        Process p1 = java.lang.Runtime.getRuntime().exec("ping -c 1 www.google.com");
        int returnVal = p1.waitFor();
        boolean reachable = (returnVal==0);
        return reachable;
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return false;
}
© www.soinside.com 2019 - 2024. All rights reserved.