我正在尝试将一堆文件添加到 C# 中的 zip 文件中,但它似乎无法正常工作。
using (var memoryStream = new MemoryStream())
{
using (var zip = new ZipArchive(memoryStream, ZipArchiveMode.Create, true))
{
for (int i = 0; i < kaart_data.GetLength(0); i++)
{
Image img = array[i];
var file = zip.CreateEntry(i + ".bmp");
using (var stream = new MemoryStream())
{
img.Save(stream, ImageFormat.Bmp);
using (var entryStream = file.Open())
{
stream.CopyTo(entryStream);
}
}
}
}
//saves the archive to disk
using (var fileStream = new FileStream(@"C:\Temp\test.zip", FileMode.Create))
{
memoryStream.Seek(0, SeekOrigin.Begin);
memoryStream.CopyTo(fileStream);
}
}
问题是它会创建 zip 文件并将其保存到磁盘中,并具有预期的文件大小。
但是当我尝试在 Windows 照片查看器中打开它们时,它们似乎已损坏。
几乎花了3个小时才弄清楚问题所在。如果你看一下原始图像和提取图像的大小,就会发现细微的差别。
using (var memoryStream = new MemoryStream())
{
using (var zip = new ZipArchive(memoryStream, ZipArchiveMode.Create, true))
{
for (var i = 0; i < images.Length; i++)
{
var img = images[i];
var file = zip.CreateEntry(i + ".bmp");
using (var stream = new MemoryStream())
{
img.Save(stream, ImageFormat.Bmp);
using (var entryStream = file.Open())
{// to keep it as image better to have it as bytes
var bytes = stream.ToArray();
entryStream.Write(bytes, 0, bytes.Length);
}
}
}
}
using (var fileStream = new FileStream(@"test.zip", FileMode.Create))
{
memoryStream.Seek(0, SeekOrigin.Begin);
memoryStream.CopyTo(fileStream);
}
}
我已经尝试过了,它的效果就像一个魅力!