如何每5分钟让人们去商店里?

问题描述 投票:1回答:1

我有如下数据表:

library(data.table)
DT1<-data.table(
  id=c(1,2,3,4,3,2),
  in_time=c("2017-11-01 08:37:35","2017-11-01 09:07:44","2017-11-01 09:46:16","2017-11-01 10:32:29","2017-11-01 10:59:25","2017-11-01 13:24:12"),
  out_time=c("2017-11-01 08:45:35","2017-11-01 09:15:30","2017-11-01 10:11:16","2017-11-01 10:37:05","2017-11-01 11:45:25","2017-11-01 14:10:09")
  )

它包含有关某人何时进入商店和离开商店的每条信息。

现在我要每5分钟带人在商店里(标准的5分钟,如分钟0,5,10,15 ... 60)。如果没有人,我需要一个0值。

所以我尝试了

library(lubridate)
DT1[,time:=ymd_hms(in_time)]
DT1[,time:=ceiling_date(time,"5mins")]
DT1[,.N,by=list(time)]

这仅给出每次输入的人数,但是我现在仍然在考虑out_time的问题。例如,id 1在2017-11-01 08:37:35输入,在2017-11-01 08:45:35保留。因此他将位于从2017-11-01 08:40:00到5分钟间隔购物2017-11-01 08:45:00而不是2017-11-01 08:50:00等。

感谢您的任何帮助。

r dplyr data.table lubridate
1个回答
0
投票

这里是使用data.table::foverlaps的选项:

times <- seq(as.POSIXct("2017-11-01 00:00:00", format=fmt), 
    as.POSIXct("2017-11-02 00:00:00", format=fmt), 
    by="5 min")
DT2 <- data.table(in_time=times[-length(times)], out_time=times[-1L], key=c("in_time","out_time"))
setkey(DT1, in_time, out_time)
foverlaps(DT2, DT1)[!is.na(id), uniqueN(id), .(i.in_time, i.out_time)]

输出的前八行:

              i.in_time          i.out_time V1
 1: 2017-11-01 08:35:00 2017-11-01 08:40:00  1
 2: 2017-11-01 08:40:00 2017-11-01 08:45:00  1
 3: 2017-11-01 08:45:00 2017-11-01 08:50:00  1
 4: 2017-11-01 09:05:00 2017-11-01 09:10:00  1
 5: 2017-11-01 09:10:00 2017-11-01 09:15:00  1
 6: 2017-11-01 09:15:00 2017-11-01 09:20:00  1
 7: 2017-11-01 09:45:00 2017-11-01 09:50:00  1
 8: 2017-11-01 09:50:00 2017-11-01 09:55:00  1

数据:

library(data.table)
DT1 <- data.table(
    id=c(1,2,3,4,3,2),
    in_time=c("2017-11-01 08:37:35","2017-11-01 09:07:44","2017-11-01 09:46:16","2017-11-01 10:32:29","2017-11-01 10:59:25","2017-11-01 13:24:12"),
    out_time=c("2017-11-01 08:45:35","2017-11-01 09:15:30","2017-11-01 10:11:16","2017-11-01 10:37:05","2017-11-01 11:45:25","2017-11-01 14:10:09")
)
cols <- c("in_time", "out_time")
fmt <- "%Y-%m-%d %T"
DT1[, (cols) := lapply(.SD, as.POSIXct, format=fmt), .SDcols=cols]
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