如何调整这个DBSCAN算法python

Question

我正在使用此聚类算法对纬度和经度点进行聚类。我正在使用预先编写的代码，该代码位于 http://scikit-learn.org/stable/auto_examples/cluster/plot_dbscan.html。

代码如下，在我的文件中包含超过 4000 个纬度和经度点。不过，我想调整此代码，使其仅将集群定义为彼此相距 0.000020 以内的点，因为我希望我的集群几乎处于街道水平。

目前我得到了 11 个簇，而理论上我想要至少 100 个簇。我尝试过调整和更改不同的数字，但无济于事。

print(__doc__)

import numpy as np

from sklearn.cluster import DBSCAN
from sklearn import metrics
from sklearn.datasets.samples_generator import make_blobs
from sklearn.preprocessing import StandardScaler


##############################################################################
# Generate sample data
input = np.genfromtxt(open("dataset_import_noaddress.csv","rb"),delimiter=",", skip_header=1)
coordinates = np.delete(input, [0,1], 1)

X, labels_true = make_blobs(n_samples=4000, centers=coordinates, cluster_std=0.0000005,
                        random_state=0)

X = StandardScaler().fit_transform(X)

##############################################################################
# Compute DBSCAN
db = DBSCAN(eps=0.3, min_samples=10).fit(X)
core_samples_mask = np.zeros_like(db.labels_, dtype=bool)
core_samples_mask[db.core_sample_indices_] = True
labels = db.labels_

# Number of clusters in labels, ignoring noise if present.
n_clusters_ = len(set(labels)) - (1 if -1 in labels else 0)

print('Estimated number of clusters: %d' % n_clusters_)
print("Homogeneity: %0.3f" % metrics.homogeneity_score(labels_true, labels))
print("Completeness: %0.3f" % metrics.completeness_score(labels_true, labels))
print("V-measure: %0.3f" % metrics.v_measure_score(labels_true, labels))
print("Adjusted Rand Index: %0.3f"
  % metrics.adjusted_rand_score(labels_true, labels))
print("Adjusted Mutual Information: %0.3f"
  % metrics.adjusted_mutual_info_score(labels_true, labels))
print("Silhouette Coefficient: %0.3f"
  % metrics.silhouette_score(X, labels))

##############################################################################
# Plot result
import matplotlib.pyplot as plt

# Black removed and is used for noise instead.
unique_labels = set(labels)
colors = plt.cm.Spectral(np.linspace(0, 1, len(unique_labels)))
for k, col in zip(unique_labels, colors):
    if k == -1:
        # Black used for noise.
        col = 'k'

    class_member_mask = (labels == k)

    xy = X[class_member_mask & core_samples_mask]
    plt.plot(xy[:, 0], xy[:, 1], 'o', markerfacecolor=col,
         markeredgecolor='k', markersize=14)

    xy = X[class_member_mask & ~core_samples_mask]
    plt.plot(xy[:, 0], xy[:, 1], 'o', markerfacecolor=col,
         markeredgecolor='k', markersize=6)

plt.title('Estimated number of clusters: %d' % n_clusters_)
plt.show()

Answer 1

您似乎仅更改了数据生成：

X, labels_true = make_blobs(n_samples=4000, centers=coordinates, cluster_std=0.0000005,
                    random_state=0)

代替聚类算法：

db = DBSCAN(eps=0.3, min_samples=10).fit(X)
            ^^^^^^^ almost your complete data set?

对于地理数据，请确保使用半正矢距离而不是欧几里德距离。地球更像是一个球体，而不是一个平坦的欧几里得世界。

Answer 2

Python 代码，集群图像

from sklearn.cluster import DBSCAN
import numpy as np
# загрузка изображения
img = plt.imread('image.jpg')
# преобразование изображения в массив точек
points = np.reshape(img,(img.shape[0]*img.shape[1], img.shape[2]))
# определение алгоритма DBSCAN с параметрами
dbscan = DBSCAN(eps=10, min_samples=10)
# выполнение кластеризации
labels = dbscan.fit_predict(points)
# преобразование меток кластеров в изображение
clustered_img = np.reshape(labels, (img.shape[0], img.shape[1]))
# вывод изображения
plt.imshow(clustered_img)
plt.show()