如何将单词添加到非唯一字符列表值

Question

def a_list（list）

list = [“ Book”，“ Glass”，“ Book，” Watch“，” Doll，“ Book”]

输出：

列表为：

书

玻璃

书

观看

娃娃

书

检查后的列表：

书

玻璃杯独特

书

观看独特

娃娃独有

书

Answer 1

一种简单的方法是：

ll=["Book","Glass","Book","Watch","Doll","Book"]
def a_list(l):
    for elem in l:
        if l.count(elem) > 1:
            print(elem)
        else:
            print(elem, "unique")

a_list(ll)

这将提供所需的输出。

如果要更改列表并返回它，则应使用相同的逻辑，但除了打印外，还应按如下方式更改元素本身：

ll=["Book","Glass","Book","Watch","Doll","Book"]
def a_list(l):
    for i, elem in enumerate(l):
        if l.count(elem) > 1:
            l[i] = "{:} unique".format(elem)
    return l

lll = a_list(ll)
print(lll)

Answer 2

您可以简单地使用collections.Counter来检测计数不超过1的唯一项目。

collections.Counter

输出：

from collections import Counter

lst=["Book","Glass","Book","Watch","Doll","Book"]

def a_list(items):

    # Count the words
    counts = Counter(items)

    for item in items:

        # Found a non-unique item, don't add "unique" to it
        if counts[item] > 1:
            print(item)

        # Found a unique item, add "unique" to it
        else:
            print(item, "unique")

a_list(lst)