Google Apps 脚本 - Google 日历 - getEvents() 多个搜索查询 - 或逻辑

Question

我正在尝试从我的谷歌日历中获取所有事件标题中包含 TERM_A 或 TERM_B 的事件。换句话说，我正在尝试在

getEvents()

函数的搜索查询中使用 OR 逻辑为

CalendarApp

.

MWE：

function mwe(){
  var mycal = "[email protected]";
  var cal = CalendarApp.getCalendarById(mycal);

  var events = cal.getEvents(new Date("June 26, 2018 00:00:00 CST"), new 
   Date("July 18, 2020 23:59:59 CST"), {search: SEARCH-FOR-TERM_A-OR-TERM_B});
  Logger.log(events);
 }
) 

我已经尝试用以下方法代替 SEARCH-FOR-TERM_A-OR-TERM_B：

• “TERM_A” | “学期 B”
• “TERM_A | TERM_B”
• “TERM_A TERM_B”
• “'TERM_A' | 'TERM_B'”

和许多这样的零成功变体。

相关提问：

• 同样的问题但是旧帖子
• 解释查询格式但未提及 OR 运算符

任何帮助将不胜感激。

Answer 1

这可能不是最好的解决方案，因为它没有在一步中利用谷歌搜索算法，但我为实现同样的目标所做的是使用两次搜索，然后连接数组：

var events = ...        
var events2 = ...
events = events.concat(events2);

以及您需要的任何其他搜索。希望对您有所帮助。

Answer 2

{搜索：TERM_A+TERM_B}

我在我的脚本中添加了以下注释以供参考：

 // Explanation of how the search section works (as it is NOT quite like most things Google) as part of the getEvents function:
  //    {search: 'word1'}              Search for events with word1
  //    {search: '-word1'}             Search for events without word1
  //    {search: 'word1 word2'}        Search for events with word2 ONLY
  //    {search: 'word1-word2'}        Search for events with ????
  //    {search: 'word1 -word2'}       Search for events without word2
  //    {search: 'word1+word2'}        Search for events with word1 AND word2
  //    {search: 'word1+-word2'}       Search for events with word1 AND without word2
  //    {search: '-word1+-word2'}      Search for events without word1 AND without word2 (I find this to work logically like an 'OR' statement)

var dateStart = sheet.getRange('C3').getValue();
var dateEnd = sheet.getRange('C4').getValue();
  // C3 and C4 are the col/row location for the date range

var events = cal.getEvents(new Date(dateStart), new Date(dateEnd), {search: 'TERM_A+TERM_B'});

Answer 3

我最后做了：

var events = cal.getEvents(new Date("January 01, 2013 00:00:00 UTC"), new Date("October 01, 2020 23:59:59 UTC"), {search: 'FIRST'});
events = events.concat(cal.getEvents(new Date("January 01, 2013 00:00:00 UTC"), new Date("October 01, 2020 23:59:59 UTC"), {search: 'SECOND'}));
events = events.concat(cal.getEvents(new Date("January 01, 2013 00:00:00 UTC"), new Date("October 01, 2020 23:59:59 UTC"), {search: 'THIRD'}));

而且效果很好...

Answer 4

谢谢，这个帖子非常有帮助，我从这里借鉴了 soem 的想法，得出以下结论：

支持一个搜索词的方法：

var calendarEntries=calendar.getEvents(fromDate,toDate,{search:searchTerm});

接受以 | 分隔的术语的新方法- 变量名称有点偏离，因为我想保留 searchTerm 作为搜索字符串，只需添加 |处理：

var calendarEntries=[];
var searchTerms=searchTerm.split("|");
for (searchKey in searchTerms){
  calendarEntries=calendarEntries.concat(calendar.getEvents(fromDate,toDate,{search:searchTerms[searchKey]}));
}

这似乎在初始测试中运行良好。