考虑此MultiIndex数据框
i = pd.MultiIndex.from_tuples([(0, 0), (0, 1), (1, 0), (1, 1)], names=['level_0', 'level_1'])
df = pd.DataFrame(range(0, 4), index=i, columns=['foo'])
和此颜色字典
colors = {0: (0.6, 0.8, 0.8, 1), 1: (1, 0.9, 0.4, 1)}
其中元组的前三项是RGB值,第四项是透明度alpha。
如何根据level_0索引对df着色?
获得此结果将很高兴:
但是这里我将考虑美术:
在后一种样式中,较亮的单元将具有相同的RGB设置,但透明度为0.25。
用途:
i = pd.MultiIndex.from_tuples([(0, 0), (0, 1), (1, 0), (1, 1)], names=['level_0', 'level_1'])
df = pd.DataFrame(range(0, 4), index=i, columns=['foo'])
#print (df)
import matplotlib.colors as col
colors = {0: (0.6, 0.8, 0.8, 1), 1: (1, 0.9, 0.4, 1)}
c = {k:col.rgb2hex(v) for k, v in colors.items()}
idx = df.index.get_level_values(0)
css = [{'selector': f'.row{i}.level0','props': [('background-color', c[v])]}
for i,v in enumerate(idx)]
print (css)
html = df.style.set_table_styles(css).render()