如何选择已订购 3 种不同产品但未订购第四种产品的客户？

Question

我有这个 SQL 查询，可以让我知道客户何时订购了某种产品：

SELECT * FROM ps_customer c
INNER JOIN ps_orders o ON (c.id_customer=o.id_customer)
INNER JOIN ps_order_detail od ON(od.id_order=o.id_order)
WHERE od.product_id=1

我希望获得订购产品 1、2、3 的客户，但绝不订购 4。

我不能简单地创建

WHERE od.product_id IN (1, 2, 3) AND od.product_id != 4

，但我一直在思考如何正确构建该查询。

仅供参考，数据库结构是基本的 Prestashop (1.6.1.4) 数据存储。

这是 SQLFiddle ： http://sqlfiddle.com/#!9/dfd65

（我无法添加数据，对于 SQLFiddle 来说太多了......）

Answer 1

也许你应该有不同的想法

SELECT * FROM ps_customer c
INNER JOIN ps_orders o ON (c.id_customer=o.id_customer)
INNER JOIN ps_order_detail od ON(od.id_order=o.id_order)
WHERE od.product_id IN (1, 2, 3)  and c.id_customer NOT IN (select id_customer from ps_orders where product_id IN (4) )

Answer 2

您可以在 id_customer 上使用几个 dinaminc 表连接

  select * from (  
        SELECT id_customer 
        FROM ps_customer c
        INNER JOIN ps_orders o ON c.id_customer=o.id_customer
        INNER JOIN ps_order_detail od ON od.id_order=o.id_order 
        WHERE od.product_id  <> 4  ) t1
  INNER JOIN (
    SELECT id_customer FROM ps_customer c
    INNER JOIN ps_orders o ON c.id_customer=o.id_customer
    INNER JOIN ps_order_detail od ON od.id_order=o.id_order 
    WHERE od.product_id in ( 1,2,3)
    having count(distinct(od.product_id)) =3
    ) t2 on t1.id_customer = t2.id_customer