我有以下
get_angles
函数,可以从 input_features
创建角度。该函数返回的特征用于训练变分量子电路。
def get_angles(x):
beta0 = 2 * np.arcsin(np.sqrt(x[1] ** 2) / np.sqrt(x[0] ** 2 + x[1] ** 2 + 1e-12))
beta1 = 2 * np.arcsin(np.sqrt(x[2] ** 2) / np.sqrt(x[2] ** 2 + x[2] ** 2 + 1e-12))
beta2 = 2 * np.arcsin(np.linalg.norm(x[2:]) / np.linalg.norm(x))
return np.array([beta2, -beta1 / 2, beta1 / 2, -beta0 / 2, beta0 / 2])
因此:
input_features = [10, 20, 30, 40, 50]`
# Transform the features
features = np.array(get_angles(input_features))
现在,我想通过获取最终的
features
值并将其转换回 input_features
函数中使用的 get_angles
值来反转此操作。有没有办法反转上面定义的get_angles
函数?
提前致谢。
期望通过
input_features
函数运行最终的 features
来接收 get_reverse_angles
,我尝试了 get_reverse_angles
函数的多种变体,例如下面的函数,但没有成功。
def get_reverse_angles(angles):
# Extract the angles
beta2, neg_beta1, pos_beta1, neg_beta0, pos_beta0 = angles
# Solve for x using trigonometric equations
x0 = np.sqrt(2)
x1 = np.sin(beta2 / 2) * np.sqrt(2)
x2 = np.sin(pos_beta1 / 2) * np.sqrt(2)
x3 = np.sin(pos_beta0 / 2) * np.sqrt(2)
x4 = np.sin(neg_beta0 / 2) * np.sqrt(2)
# Compute x0 using the first equation
x0 = np.sqrt(x1 ** 2 + x2 ** 2 + x3 ** 2 + x4 ** 2)
# Return the values of the reversed operation
return np.array([x0, x1 * x0, x2 * x0, x3 * x0, x4 * x0])
get_reverse_angles
函数返回 [ 1.79350156 2.41835701 0.97063605 1.33346136 -1.33346136],而不是预期的 [10 20 30 40 50] input_features
。
def inverse_get_angles(features):
beta0 = 2 * np.sin(features[4] / 2)
beta1 = 2 * np.sin(-features[2] / 2)
beta2 = 2 * np.sin(features[0] / 2)
x0 = np.sin(beta0) * np.sqrt(np.sum([x ** 2 for x in [10, 20, 30, 40, 50]]))
x1 = np.sin(beta1) * np.sqrt(np.sum([x ** 2 for x in [30, 30, 40, 50]]))
x2 = np.sin(beta2) * np.sqrt(np.sum([x ** 2 for x in [40, 50]]))
return [x0, x1, x1, x2, x2]
inverse_input_features = inverse_get_angles(features)
print(input_features)