Python Klein-非阻塞API

Question

需要有关Klein API的无阻塞帮助这是简单的测试应用程序：

# -*- coding: utf-8 -*-
from klein import Klein
import json
import time
import datetime

app = Klein()


async def delay(seconds):
"""Set some delay for test"""
  time.sleep(seconds)
  return "Works"


@app.route('/', branch=True)
async def main(request):
  some_data = await delay(5)

  return json.dumps([
    {
        "status":   "200",
        "time":     datetime.datetime.now().strftime("%Y-%m-%d %H:%M:%S"),
        "data":     some_data
    }
  ])

app.run("localhost", 8080)

比简单地运行我的server.py并同时向http://127.0.0.1:8080/发出2个请求。结果：

[{“ status”：“ 200”，“ time”：“ 2019-10-18 20:57:16”，“数据”：“作品”}]

[{“ status”：“ 200”，“ time”：“ 2019-10-18 20:57:21”，“数据”：“作品”}]

每个响应之间延迟5秒。

问题：

如何使此代码同时处理两个请求，现在可以一个接一个地工作...

也尝试使用扭曲，结果相同

PYTHONPATH =。扭曲--pidfile = apserver.pid -n web --class = api.resource --port tcp：8000：interface = 0.0.0.0

谢谢

Answer 1

所以，问题出在您的delay函数-它是一个阻塞函数，因为python的time.sleep-正在阻塞。有关更多信息，您可以阅读here。

您的问题的解决方案是使用task.deferLater，如下所示

task.deferLater

并且输出应该是

# -*- coding: utf-8 -*-
import datetime
import json

import treq
from klein import Klein
from twisted.internet import task, reactor

app = Klein()

async def delay1(secs):
    await task.deferLater(reactor, secs)
    return "Works"

def delay2(secs):
    return task.deferLater(reactor, secs, lambda: "Works")

@app.route('/', branch=True)
async def main(request):
    some_data = await delay1(5)  # or some_data = await delay2(5) 

    return json.dumps([{
        "status": "200",
        "time": datetime.datetime.now().strftime("%Y-%m-%d %H:%M:%S"),
        "data": some_data
    }])

def send_requests():
    for i in range(2):
        print("request", datetime.datetime.now().strftime("%Y-%m-%d %H:%M:%S"))
        d = treq.get('http://localhost:8080')
        d.addCallback(treq.content)
        d.addCallback(lambda x: print("response", x.decode()))

# send requests every 10 seconds
repeating = task.LoopingCall(send_requests)
repeating.start(10, now=False)

app.run("localhost", 8080)