多元线性回归成本太高

问题描述 投票:0回答:1

我正在使用this链接imports-85.data中提供的数据集进行价格预测。

[使用horsepowercurb-weightengine-sizehighway-mpg,我尝试归一化(由于成本高)并通过实现以下操作来运行梯度下降算法:

初始化

data = df[attrs]
m = len(data) # m-training examples
f = len(attrs) # n-features
X = np.hstack((np.ones(shape=(m,1)),np.array(data)))
T = np.zeros(f + 1) # Coefficients of x(0),x(1),...x(n)
norm_price = df.price / 1000
Y = np.array(norm_price)

# Normalization
data['curb-weight'] = (data['curb-weight'] * 0.453592) / 1000    # To kg (e-1000)
data['highway-mpg'] = data['highway-mpg'] * 0.425144    # To km per litre (kml)
data['engine-size'] = data['engine-size'] / 100     # To e-100
data['horsepower'] = data['horsepower'] / 100   # To e-100

col_rename = {
    'curb-weight':'curb-weight-kg(e-1000)',
    'highway-mpg':'highway-kml',
    'engine-size':'engine-size(e-100)',
    'horsepower':'horsepower(e-100)'
}
data.rename(columns=col_rename,inplace=True)

成本计算

def calculateCost():
    global m,T,X
    hypot = (X.dot(T) - Y).transpose().dot(X.dot(T) - Y)
    return hypot / (2 * m)

梯度下降

def gradDescent(threshold,iter = 10000,alpha = 3e-8):
    global T,X,Y,m
    i = 0
    cost = calculateCost()
    cost_hist = [cost]
    while i < iter:
        T = T - (alpha / m) * X.transpose().dot(X.dot(T) - Y)
        cost = calculateCost()
        cost_hist.append(cost)
        i += 1
        if cost <= threshold:
            return cost_hist

我通过此实现进行了梯度下降:Batch Gradient Descent

没有标准化,成本将是118634960.460199。使用归一化,成本将为118.634960460199

因此,我有几个问题:

  1. 我的归一化技术正确吗?
  2. 归一化后,成本会有所不同。归一化后如何设置成本阈值?
python machine-learning linear-regression gradient-descent non-linear-regression
1个回答
0
投票

我认为您可能会在机器学习的背景下误解“规范化”。根据我对代码的解释,您的“规范化”部分正在进行单位转换。在进行渐变样之前,通常应用最大-最小缩放或标准缩放,请参见scikit learn user guide。这些技术创建的特征具有更一致的分布,因此单个特征的更改不会完全支配损耗函数。

© www.soinside.com 2019 - 2024. All rights reserved.