合并对象的ArraList，不含公有制，并保留Java中所有对象的所有归档值[已关闭]。

Question

封闭. 这个问题需要更多 集中. 目前不接受回答。

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封闭 2个月前.

改进这个问题

我有两个对象的ArrayList，比如

ArrayList<Record>  dataSetOne;
ArrayList<Record>  dataSetTwo;

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其中记录对象的样子

public class Record{
  private String id;
private String name;
private String HomeAdrress;
private String OfficeAdrress;
}

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所以，在第一个ArrayList，即dataSetOne中，我将得到与家庭住址相关的记录数据，在第二个ArrayList，即dataSetTwo中，我将得到与办公室地址相关的记录数据。

public class Record{
  id = emp01;
 name = andy;
 HomeAdrress = mexico;
}

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在第二个ArrayList中，即dataSetTwo中，我将得到与办公室地址相关的详细记录数据。

public class Record{
   id = emp01;
   name = andy;
   officeAdrress = california;
}

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所以要求是我需要合并这两个数组列表，并结合以id为主的记录，并得到家庭和办公室地址，就像下面这样。

public class Record{
  id = emp01;
   name = andy;
  HomeAdrress = mexico;
   officeAdrress = california;
}

谅谅

Answer 1

import java.util.*;

/* define your IncompleteRecordErr here */
class IncompleteRecordException extends Exception {
    IncompleteRecordException() {    
        super("Your record is incomplete. Vital data missing!");
    }
}

/* */
class Record {
    public int id;
    public String name;
    public String homeAddress;
    public String officeAdrress;
}

public class App {
    public static void main(String[] args) {
        ArrayList<Record> arrList1 = new ArrayList<>();
        ArrayList<Record> arrList2 = new ArrayList<>();
        /* full your arrLists above with elements */

        ArrayList<Record> merged = new ArrayList<>();
        for(int i = 0; i < arrList1.size(); i++) { // supposed both data lists have same len        
            Record r1 = arrList1.get(i);
            Record r2 = arrList2.get(i);
            Record currentRecord = new Record();
            if(r1.id != 0) currentRecord.id = r1.id; // check for not default value
            else if(r2.id != 0) currentRecord.id = r2.id;
            //else throw new IncompleteRecordException();

            if(r1.name != null) currentRecord.name = r1.name;
            else if(r2.name != null) currentRecord.name = r2.name;
            //else throw new IncompleteRecordException();

            if(r1.homeAddress != null) currentRecord.homeAddress = r1.homeAddress;
            else if(r2.homeAddress != null) currentRecord.homeAddress = r2.homeAddress;
            //else throw new IncompleteRecordException();

            if(r1.officeAdrress != null) currentRecord.officeAdrress = r1.officeAdrress;
            else if(r2.officeAdrress != null) currentRecord.officeAdrress = r2.officeAdrress;
            //else throw new IncompleteRecordException();

            merged.add(currentRecord);
        }
    // now, "merged" should contain your merged data
    }
}

Answer 2

Record类必须是:

class Record{
  public int id;
  public String name;
  public String homeAddress;
  public String officeAdrress;
  }

和主函数。

public static void main(String[] args) {
    ArrayList<Record> merged = new ArrayList<>();
    Record r;
    for(int i = 0; i < dataSetOne.size(); i++) {
       for(int j = 0; j < dataSetTwo.size(); j++){
         if(dataSetOne.get(i).id == dataSetTwo.get(j).id){
           r = new Record();
           r.id = dataSetOne.get(i).id;
           r.name=dataSetOne.get(i).name;
           r.homeAddress = dataSetOne.get(i).homeAddress;
           r.officeAdrress = dataSetTwo.get(j).officeAdrress;
           merged.add(r);
         }
       }
    }
}