我有一个数据框,如下所示:
+-----+---------+-----+-----+-----------------+----------+----------+------------+
| ID | CURRENT | JAN | FEB | CURRENT_IN_2018 | JAN_2018 | FEB_2018 | UNITS_SWAP |
+-----+---------+-----+-----+-----------------+----------+----------+------------+
| 123 | 2 | 3 | 4 | 5 | 6 | 7 | 12 |
| 456 | 1 | 5 | 0 | 4 | 8 | 6 | 6 |
+-----+---------+-----+-----+-----------------+----------+----------+------------+
我在这里要做的是依次从UNITS_SWAP
,CURRENT_IN_2018
和JAN_2018
中减去FEB_2018
中的数字,直到UNITS_SWAP中的数字达到零。同样,在执行此操作时,请将每行减去的UNITS_SWAP
的数量添加到其相应的匹配行中,例如,如果从current_in_2018中减去5个单位,则在CURRENT中添加5个单位,依此类推,对于JAN和FEB,以此类推最终结果如下:
+-----+---------+-----+-----+-----------------+----------+----------+------------+
| ID | CURRENT | JAN | FEB | CURRENT_IN_2018 | JAN_2018 | FEB_2018 | UNITS_SWAP |
+-----+---------+-----+-----+-----------------+----------+----------+------------+
| 123 | 7 | 9 | 5 | 0 | 0 | 6 | 0 |
| 456 | 5 | 7 | 0 | 0 | 6 | 6 | 0 |
+-----+---------+-----+-----+-----------------+----------+----------+------------+
加载数据的脚本:
DF <- data.frame(ID = c(123,456),
CURRENT = c(2,1),
JAN = c(3,5),
FEB=c(4,0),
CURRENT_2018 = c(5,4),
JAN_2018 = c(6,8),
FEB_2018=c(7,6),
UNITS_SWAP =c(12,6))
您可以执行此操作-但请注意,它将覆盖您的源DF:
cols <- c('CURRENT', 'JAN', 'FEB')
for (i in 1:NROW(DF)) {
while (DF[i, 'UNITS_SWAP'] > 0) {
for (col in cols) {
excess <- min(DF[i,'UNITS_SWAP'], DF[i, paste0(col, '_2018')])
DF[i, col] <- DF[i, col] + excess
DF[i, paste0(col, '_2018')] <- DF[i, paste0(col, '_2018')] - excess
DF[i, 'UNITS_SWAP'] <- DF[i, 'UNITS_SWAP'] - excess
}
}
}
因为您的列具有确定的结构(column
匹配column_2018
),所以我们只需要按照您指定的顺序遍历它们,然后粘贴_2018
以获得相关的匹配列。