将带有以太坊地址的数组传递给控制器会向我显示错误尝试获取非对象的属性“地址”
我正在开发一个带有Laravel和区块链以太坊的Dapp,我已经配置了自己的以太坊节点
我有一个带有公共函数的BaseController,它将JSONRPC调用到URL API并向RegisterController返回一个地址,但它在代码行'address'=> $中出现了一个错误,试图获取非对象的属性'address' taddress->地址
有谁可以帮助我吗?
我留下每个控制器的代码
BaseController
public function get_address()
{
$fields = [
"jsonrpc" => '2.0',
"method" => 'eth_accounts',
// "method" => 'personal_newAccount',
// "method" => 'createAddressForToken',
"params" => ['password'],
"id" => '1',
];
$fields = json_encode($fields);
$headers = [
'Content-Type: application/json',
];
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, APIURL);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $fields);
$result = curl_exec($ch);
curl_close($ch);
$response = json_decode($result);
if (isset($response->error->code)) {
return $address = 0;
} else {
return $address = $response->result;
}
}
RegisterController
protected function create(array $data)
{
$settings = AdminSettings::first();
// Verify Settings Admin
if ($settings->email_verification == 1) {
$confirmation_code = str_random(100);
$status = 'pending';
//send verification mail to user
$_username = $data['name'];
$_email_user = $data['email'];
$_title_site = $settings->title;
$_email_noreply = $settings->email_no_reply;
Mail::send('emails.verify', ['confirmation_code' => $confirmation_code, 'title_site' => $_title_site],
function ($message) use (
$_username,
$_email_user,
$_title_site,
$_email_noreply
) {
$message->from($_email_noreply, $_title_site);
$message->subject(trans('users.title_email_verify'));
$message->to($_email_user, $_username);
});
} else {
$confirmation_code = '';
$status = 'active';
}
$token = str_random(75);
$taddress = $this->get_address();
json_encode($taddress);
var_dump($taddress);
return User::create([
'name' => $data['name'],
'email' => $data['email'],
'password' => bcrypt($data['password']),
'countries_id' => $data['countries_id'],
'avatar' => 'default.jpg',
'status' => $status,
'role' => 'normal',
'token' => $token,
'confirmation_code' => $confirmation_code,
'address' => $taddress->address,
//'address' => $taddress,
'private_key' => $taddress->password,
]);
}
我感谢任何帮助:)
您的退货声明中有错误。您将返回变量赋值的结果,而您应该只返回变量。
这导致行$taddress = $this->get_address();
不是一个对象,但很可能是一个布尔值。这会导致您的错误。
if (isset($response->error->code)) {
return $address = 0;
} else {
return $address = $response->result;
}
应改为:
if (isset($response->error->code)) {
return 0;
} else {
return $response->result;
}
非常感谢您的回答!
我做了改变,就像他们在BaseController中告诉我的那样:
if(isset($response->error->code))
{
return $address=0;
}
else
{
return $response->result;
//return $address=$response->result;
}
但它在代码行中的RegisterController中一直显示相同的错误:
'address' => $taddress->address
会是什么呢