python如何三击选择段落？

Question

有人请告诉我一种三次单击 selenium python 的方法。我试过这个和其他东西，但没有用。

for x in range(3)
   actions.click()

Answer 1

Selenium 的当前实现不提供任何执行三次单击的方法。然而，一种可行的方法是使用 execute_script() 方法模拟所需的

鼠标事件

，如下所示：

def  js_triple_click(element, deltaY = 60, offsetX = 0, offsetY = 0):
    driver.execute_script("""
      "var target = arguments[0];                                 " +
      "var offsetX = arguments[1];                                " +
      "var offsetY = arguments[2];                                " + 
      "var rect = target.getBoundingClientRect();                 " +
      "var cx = rect.left + (offsetX || (rect.width / 2));        " +        
      "var cy = rect.top + (offsetY || (rect.height / 2));        " +
      "                                                           " +
      "emit('mousedown', {clientX: cx, clientY: cy, buttons: 1}); " +
      "emit('mouseup',   {clientX: cx, clientY: cy});             " +
      "emit('mousedown', {clientX: cx, clientY: cy, buttons: 1}); " +
      "emit('mouseup',   {clientX: cx, clientY: cy});             " +
      "emit('mousedown', {clientX: cx, clientY: cy, buttons: 1}); " +
      "emit('mouseup',   {clientX: cx, clientY: cy});             " +
      "emit('click',     {clientX: cx, clientY: cy, detail: 3});  " +
      "                                                           " +
      "function emit(name, init) {                                " +
    "target.dispatchEvent(new MouseEvent(name, init));        " +
      "}                                                          " ;
    """)

element = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.TAG_NAME, "p"))) # replace the locator as per your usecase
ActionChains(driver).move_to_element(element).perform()
js_triple_click(element)
print("Tripple click performed")

控制台输出：

Tripple click performed

Answer 2

这将三次单击您在此页面上提出的问题。希望能帮助到你。棘手的部分是 pyautogui 不关心浏览器窗口的位置。

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import pyautogui


driver = webdriver.Firefox(executable_path=r'C:\\Path\\To\\Your\\geckodriver.exe')
driver.get('https://stackoverflow.com/questions/63253535/how-to-triple-click-on-python-to-select-a-paragraph')
driver.maximize_window()

test_paragraph = WebDriverWait(driver, 10).until(
    EC.element_to_be_clickable((By.XPATH, "//p[contains(text(), 'Someone please tell me a way to triple-click ')]")))

# import time
# time.sleep(3)
panel_height = driver.execute_script('return window.outerHeight - window.innerHeight;')
abs_x = test_paragraph.location['x']
y = test_paragraph.location['y']
abs_y = y + panel_height
print("Absolute x : " + str(abs_x))
print("Absolute y : " + str(abs_y))

pyautogui.moveTo(abs_x + 10, abs_y)
pyautogui.click(clicks=3)

Answer 3

我会说你错过了表演动作：

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains

driver = webdriver.Chrome()
actions = ActionChains(driver)
for i in range(3):
    actions.click()
    actions.perform()
    print('click')

现在有用吗？

更新的答案 尝试找到两个元素，然后使用 drag_and_drop 将这些元素作为命令的源和结尾。下面的代码似乎有效并选择了段落。

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains

driver = webdriver.Chrome()
driver.get("https://en.wikipedia.org/wiki/Home")
actions = ActionChains(driver)
# first element and last element in the paragraph
start = driver.find_element_by_xpath('//*[@id="mw-content-text"]/div/div[1]')
end = driver.find_element_by_xpath('//*[@id="mw-content-text"]/div/div[4]')

actions.drag_and_drop(start, end).perform()

我用维基百科做测试，我取了两行文字的xpath。脚本选择了中间的段落。所以应该没问题。让我知道

Answer 4

您需要导入：

from selenium.webdriver.common.action_chains import ActionChains

那你可以试试这个：

times = 3
while(times >0):
            ActionChains(driver).click().perform()
            times -= 1;

Answer 5

或者，您可以尝试对其进行硬编码。

actions = ActionChains(driver)

def triple_click(element_x):
    actions.click(element_x).click(element_x).click(element_x).perform()

triple_click(your_element)

Answer 6

如果时间不是问题，你可以逃脱：

actions = ActionChains(driver)
actions.double_click()
actions.click()
actions.perform()

否则您可以直接构建自己的 w3c 操作：

actions = ActionChains(driver)
actions.move_to_element(element)
actions.w3c_actions.pointer_action.click()
actions.w3c_actions.pointer_action.click()
actions.w3c_actions.pointer_action.click()
# don't forget to add a slight pause -- see actions.double_click()
for _ in range(4):
    actions.w3c_actions.key_action.pause()