如何在单个数据框列中记录是否存在大字符串的拆分元素

问题描述 投票:0回答:1

我有一个数据框,其中包含一连串混乱的家庭设施。我想将字符串分解为唯一的便利设施,为每个唯一的便利设施在数据框中创建一个新列,并在新列中记录字符串中各个便利设施的存在/不存在。使用嵌套的for循环,我找到了一种完成任务的方法。但是,我想知道的是如何使用apply系列函数或dplyr方法之一来避免循环,从而获得相同的结果。

可复制数据:

df <- data.frame(
  id = 1:4,
  amenities = c('{"Wireless Internet","Wheelchair accessible",Kitchen,Elevator,"Buzzer/wireless intercom",Heating}',
                '{TV,"Cable TV",Internet,"Wireless Internet","Air conditioning",Kitchen,"Smoking allowed","Pets allowed"}',
                '{"Buzzer/wireless intercom",Heating,"Family/kid friendly","Smoke detector",Carbon monoxide}',
                '{Washer,Dryer,Essentials,Shampoo,Hangers,"Laptop friendly workspace"}'))

到目前为止,我所做的是:

amenities_clean <- gsub('[{}"]', '', df$amenities) # remove unwanted stuff 
amenities_split <- strsplit(amenities_clean, ",") # split rows into individual amenities
amenities_unique <- unique(unlist(strsplit(amenities_clean, ","))) # get a list of unique amenities 
df[amenities_unique] <- NA # set up the columns for each amenity

要在新列中记录字符串中是否存在单个便利设施,我正在使用str_detect以及嵌套的for循环:

# record presence/absence of individual amenities in each new column:
library(stringr)
for(i in 1:ncol(df[amenities_unique])){
  for(j in 1:nrow(df)){
    df[amenities_unique][j,i] <- 
      ifelse(str_detect(amenities_split[j], names(df[amenities_unique][i])), 1, 0)
  }
}

虽然这会产生警告,但它们似乎无害,因为结果看起来还不错:

df
  id                                                                                                amenities Wireless Internet
1  1        {"Wireless Internet","Wheelchair accessible",Kitchen,Elevator,"Buzzer/wireless intercom",Heating}                 1
2  2 {TV,"Cable TV",Internet,"Wireless Internet","Air conditioning",Kitchen,"Smoking allowed","Pets allowed"}                 1
3  3              {"Buzzer/wireless intercom",Heating,"Family/kid friendly","Smoke detector",Carbon monoxide}                 0
4  4                                    {Washer,Dryer,Essentials,Shampoo,Hangers,"Laptop friendly workspace"}                 0
  Wheelchair accessible Kitchen Elevator Buzzer/wireless intercom Heating TV Cable TV Internet Air conditioning Smoking allowed
1                     1       1        1                        1       1  0        0        1                0               0
2                     0       1        0                        0       0  1        1        1                1               1
3                     0       0        0                        1       1  0        0        0                0               0
4                     0       0        0                        0       0  0        0        0                0               0
  Pets allowed Family/kid friendly Smoke detector Carbon monoxide Washer Dryer Essentials Shampoo Hangers Laptop friendly workspace
1            0                   0              0               0      0     0          0       0       0                         0
2            1                   0              0               0      0     0          0       0       0                         0
3            0                   1              1               1      0     0          0       0       0                         0
4            0                   0              0               0      1     1          1       1       1                         1

给出警告并考虑到嵌套循环的复杂性,如何使用apply函数族中的函数或使用dplyr来获得相同的结果?

r dplyr apply lapply sapply
1个回答
0
投票

一旦清洁便利设施,就可以使用cSplit_e中的splitstackshape

df$amenities_clean <- gsub('[{}"]', '', df$amenities) 
splitstackshape::cSplit_e(df, "amenities_clean", type = "character", fill = 0)
© www.soinside.com 2019 - 2024. All rights reserved.