从Ruby接受字符串和XML数据

问题描述 投票：0回答：1

我想创建REST服务器，它接受来自Ruby代码的XML请求和纯文本到不同的控制器。我试图实现这个：

@SpringBootApplication
public class Application extends SpringBootServletInitializer implements WebMvcConfigurer {

    @Override
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
        return application.sources(Application.class);
    }
    ..............

    @Override
    public void extendMessageConverters(List<HttpMessageConverter<?>> converters) {
        converters.removeIf(converter -> converter instanceof MappingJackson2XmlHttpMessageConverter);
        converters.removeIf(converter -> converter instanceof MappingJackson2HttpMessageConverter);
        converters.add(new MappingJackson2XmlHttpMessageConverter(
                ((XmlMapper) createObjectMapper(Jackson2ObjectMapperBuilder.xml()))
                        .enable(ToXmlGenerator.Feature.WRITE_XML_DECLARATION)));
        converters.add(new MappingJackson2HttpMessageConverter(createObjectMapper(Jackson2ObjectMapperBuilder.json())));
    }

    private ObjectMapper createObjectMapper(Jackson2ObjectMapperBuilder builder) {
        builder.indentOutput(true);
        builder.modules(new JaxbAnnotationModule());
        builder.serializationInclusion(JsonInclude.Include.NON_NULL);
        builder.defaultUseWrapper(false);
        return builder.build();
    }    
}

@Configuration
public class WebConfiguration implements WebMvcConfigurer {

    @Override
    public void configureMessageConverters(List<HttpMessageConverter<?>> converters) {
        //MyRequestBodyHttpMessageConverter converter = new MyRequestBodyHttpMessageConverter();
        FormHttpMessageConverter converter = new FormHttpMessageConverter();
        //MediaType utf8FormEncoded = new MediaType("application","x-www-form-urlencoded", Charset.forName("UTF-8"));
        //MediaType mediaType = MediaType.APPLICATION_FORM_URLENCODED; maybe UTF-8 is not needed
        converter.setSupportedMediaTypes(Arrays.asList(MediaType.APPLICATION_FORM_URLENCODED));
        //converter.setSupportedMediaTypes(Arrays.asList(utf8FormEncoded));
        converters.add(converter);
        MappingJackson2HttpMessageConverter conv1 = new MappingJackson2HttpMessageConverter();
        conv1.getObjectMapper().registerModule(new JaxbAnnotationModule());
        converters.add(conv1);

        MappingJackson2XmlHttpMessageConverter conv = new MappingJackson2XmlHttpMessageConverter();
        // required by jaxb annotations
        conv.getObjectMapper().registerModule(new JaxbAnnotationModule());
        converters.add(conv);
    }
}

检查XML格式正确：

@ControllerAdvice
public class RestExceptionHandler extends ResponseEntityExceptionHandler {

    @Override
    protected ResponseEntity<Object> handleHttpMessageNotReadable(HttpMessageNotReadableException ex,
                                                                  HttpHeaders headers, HttpStatus status, WebRequest request) {
        PaymentTransaction response;
        if (ex.getMessage().contains("Required request body")) {
            response = new PaymentTransaction(PaymentTransaction.Response.failed_response, 350,
                    "Invalid XML message: No XML data received", "XML request parsing failed!");
        } else {
            response = new PaymentTransaction(PaymentTransaction.Response.failed_response, 351,
                    "Invalid XML message format", null);
        }
        return ResponseEntity.badRequest().body(response);
    }
}

控制器类：

@RestController()
public class HomeController {

    @Autowired
    public HomeController(Map<String, MessageProcessor> processors, Map<String, ReconcileProcessor> reconcileProcessors,
            @Qualifier("defaultProcessor") MessageProcessor defaultProcessor,
            AuthenticationService authenticationService, ClientRepository repository,
            @Value("${request.limit}") int requestLimit) {
        // Here I receive XML 
    }

    @GetMapping(value = "/v1/*")
    public String message() {
        return "REST server";
    }

    @PostMapping(value = "/v1/{token}", consumes = { MediaType.APPLICATION_XML_VALUE,
            MediaType.APPLICATION_JSON_VALUE }, produces = { MediaType.APPLICATION_XML_VALUE,
                    MediaType.APPLICATION_JSON_VALUE })
    public PaymentResponse handleMessage(@PathVariable("token") String token,
            @RequestBody PaymentTransaction transaction, HttpServletRequest request) throws Exception {
        // Here I receive XML 
    }

    @PostMapping(value = "/v1/notification")
    public ResponseEntity<String> handleNotifications(@RequestBody Map<String, String> keyValuePairs) {
         // Here I receive key and value in request body
    }

    @PostMapping(value = "/v1/summary/by_date/{token}", consumes = { MediaType.APPLICATION_XML_VALUE,
            MediaType.APPLICATION_JSON_VALUE }, produces = { MediaType.APPLICATION_XML_VALUE,
                    MediaType.APPLICATION_JSON_VALUE })
    public PaymentResponses handleReconcile(@PathVariable("token") String token, @RequestBody Reconcile reconcile,
            HttpServletRequest request) throws Exception {
         // Here I receive XML 
    }

    @ResponseStatus(value = HttpStatus.UNAUTHORIZED)
    public static class UnauthorizedException extends RuntimeException {
        UnauthorizedException(String message) {
            super(message);
        }
    }
}

正如您在某些方法中看到的那样，我收到了XML，而在其他方法中，我收到了key=value&.....形式的String

我如何配置Spring接受这两种类型？我还应该将Rest控制器拆分成不同的文件吗？

编辑：

示例XML请求：

<?xml version="1.0" encoding="UTF-8"?>
<payment_transaction>
  <transaction_type>authorize</transaction_type>
  <transaction_id>2aeke4geaclv7ml80</transaction_id>
  <amount>1000</amount>
  <currency>USD</currency>
  <card_number>22</card_number>
  <shipping_address>
    <first_name>Name</first_name>    
  </shipping_address>
</payment_transaction>

XML响应示例：

<?xml version="1.0" encoding="UTF-8"?>
<payment_response>
    <transaction_type>authorize</transaction_type>
    <status>approved</status>
    <unique_id>5f7edd36689f03324f3ef531beacfaae</unique_id>
    <transaction_id>asdsdlddea4sdaasdsdsa4dadasda</transaction_id>
    <code>500</code>
    <amount>101</amount>
    <currency>EUR</currency>
</payment_response>

样品通知请求：

uniqueid=23434&type=sale&status=33

示例通知响应：它应该只返回HTTP状态OK。

我用：

    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.0.4.RELEASE</version>
        <relativePath />
    </parent>

Java版本：“10.0.2”2018-07-17和Wildfly 13。

关于我使用的XML生成：

@XmlRootElement(name = "payment_transaction")
public class PaymentTransaction {

    public enum Response {
        failed_response, successful_response
    }

    @XmlElement(name = "transaction_type")
    public String transactionType;
    @XmlElement(name = "transaction_id")
    public String transactionId;
    @XmlElement(name = "usage")

POM配置：https://pastebin.com/zXqYhDH3

java spring spring-boot spring-restcontroller spring-rest
1个回答
0
投票

当在WildFly上部署为WAR应用程序时，Spring Boot应用程序可能需要一些用于代理的高级JDK反射API，包含在sun.reflect包中。为此，您的应用程序需要在其MANIFEST.MF文件中列出jdk.unsupported作为依赖项（请参阅WildFly wiki）。

source - 所以我先应用了这个。

<plugin>
    <artifactId>maven-war-plugin</artifactId>
    <version>3.2.2</version>
    <configuration>
        <packagingExcludes>WEB-INF/web.xml</packagingExcludes>
        <archive>
            <manifestEntries>
                <Dependencies>jdk.unsupported</Dependencies>
            </manifestEntries>
        </archive>
    </configuration>
</plugin>

接下来，我修复了日志记录：我将the first comment of the accepted answer here应用于日志记录，并从此处添加了basic logback.xml到src / main / resources。

所以我的基本jboss-deployment-structure.xml如下：

<?xml version="1.0" encoding="UTF-8"?>
<jboss-deployment-structure>
    <deployment>
        <exclude-subsystems>
            <subsystem name="logging" />
        </exclude-subsystems>
    </deployment>
</jboss-deployment-structure>

从现在开始，在Wildfly控制台中，您可以看到发生了什么。

我在两个发行版中测试了一个POC：

仅Servlet分发（wildfly-servlet-13.0.0.Final.zip）

这适用于基本的jboss-deployment-structure.xml。

应用程序服务器分发（wildfly-13.0.0.Final.zip）

在这个服务器中，我不得不添加org.reactivestreams模块：

<?xml version="1.0" encoding="UTF-8"?>
<jboss-deployment-structure>
    <deployment>
        <exclude-subsystems>
            <subsystem name="logging" />
        </exclude-subsystems>
        <dependencies>
            <module name="org.reactivestreams"/>
        </dependencies>
    </deployment>
</jboss-deployment-structure>

您必须将此文件放在src / main / webapp / WEB-INF目录中。

如果您需要使用支持不同于application / x-www-form-urlencoded的内容类型，您可以通过向内容类型注册正确的MessageConverter来实现。

在您的情况下，由于请求体中的查询字符串，FormHttpMessageConverter将是“正确的”，您必须将内容类型指定为MY_OTHER_CONTENT_TYPE常量：

@Override
public void configureMessageConverters(List<HttpMessageConverter<?>> converters) {
    FormHttpMessageConverter converter = new FormHttpMessageConverter();
    MediaType utf8FormEncoded = new MediaType("application","x-www-form-urlencoded", Charset.forName("UTF-8"));
converter.setSupportedMediaTypes(Arrays.asList(MediaType.APPLICATION_FORM_URLENCODED, MY_OTHER_CONTENT_TYPE));
    converters.add(converter);
    super.configureMessageConverters(converters);
}

然而，使用过的转换器应该能够处理它，所以你必须检查转换器的来源（我做了，如果是FormHttpMessageConverter，它应该以这种方式工作）我想（或者你可以尝试一下，如果它有效，有效）。有时这不是simple，但我希望你能以这种方式工作。

如果你无法解决它，请给我们一个有问题的请求的完整样本，我会尝试让它工作。

去测试

请确保您使用带有POST方法的Content-Type：application / x-www-form-urlencoded标头，并且您的参数正在请求正文中。 （我已经使用Boomerang Chrome插件进行测试，当我为post请求定义请求参数时，它将请求URL添加为get参数。这显然导致了错误的结果。）

我希望这些能帮到你。如果没有，在您应用正确的日志记录设置后，您将能够告诉我们原因（请更新您的帖子，但有例外）。

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