JMS连接到远程客户端

Question

我正在尝试测试JMS应用程序，我没有消费者的问题，但是当我尝试运行具有以下代码的生产者时

public class QueueProducer {

    /**
     * @param args
     * @throws NamingException
     * @throws JMSException
     */
    public static void main(String[] args) throws JMSException, NamingException {
        System.out
                .println("--------Entering JMS Example QueueProducer--------");
        Context context = QueueConsumer.getInitialContext();
        QueueConnectionFactory queueConnectionFactory = (QueueConnectionFactory) context
                .lookup("ConnectionFactory");
        Queue queue = (Queue) context
                .lookup("queue/zaneacademy_jms_tutorial_02");
        QueueConnection queueConnection = queueConnectionFactory
                .createQueueConnection();
        QueueSession queueSession = queueConnection.createQueueSession(false,
                QueueSession.AUTO_ACKNOWLEDGE);
        queueConnection.start();
        QueueProducer queueProducer = new QueueProducer();
        queueProducer.sendMessage("Message 1 From QueueProducer...",
                queueSession, queue);
        System.out.println("--------Exiting JMS Example QueueProducer--------");
    }

    public void sendMessage(String text, QueueSession queueSession, Queue queue)
            throws JMSException {
        QueueSender queueSender = queueSession.createSender(queue);
        TextMessage textMessage = queueSession.createTextMessage(text);
        queueSender.send(textMessage);
        System.out.println("Message Sent : "+textMessage.getText());
        queueSender.close();
    }

}

它只显示生产者中的消息，几秒钟后显示此警告

 WARN  [SimpleConnectionManager] A problem has been detected with the connection to remote client 5c4o12-  tsh1gl-hfybsrs4-1-hfybss2a-4, jmsClientID=b-l5ssbyfh-1-4srsbyfh-lg1hst-21o4c5. It is possible the client has exited without closing its connection(s) or the network has failed. All associated connection resources will be cleaned up.

Answer 1

可能需要关闭队列连接。 尝试添加queueConnection.close(); 在main结束时。

此外，需要关闭的资源应该在finally块中完成。 即使在使用资源时发生异常，这也可确保资源处于关闭状态。 例如：

QueueSender queueSender = ...
try {
    // use queueSender
}
finally {
    queueSender.close();
}

queueConnection 。

Answer 2

我遇到了同样的问题。 我认为QueueConnection和QueueSession需要关闭。在上面的代码片段中，附加代码应该是：

        queueConnection.stop();
        queuesession.close();
        queueConnection.close();

在此之后我的问题得到了解决。