我正在使用maven tomcat插件来部署应用程序。如果我设置<path>/<path>
的路径,它确实在根上下文中部署,但我想知道它是否会导致任何问题,因为the docs明确说“不要使用/”。
相关问题:How to set context path to root(“/”) in Tomcat 7.0 when using Maven
为什么不在maven tomcat中使用/作为路径?
在此提交中引入了指向“不使用/”的JavaDoc:
向下滚动提交时,您会看到path
属性值用于创建JarArchiveEntry
:
os.putArchiveEntry( new JarArchiveEntry( path + ".war" ) );
对于配置的<path>/<path>
,它将转换为文件名“/.war”,看起来有点无效。另一方面,这可能会在提取时产生“.war”文件名。
今天版本2.2这段代码看起来像bug MTOMCAT-103改变了:
os.putArchiveEntry(
new JarArchiveEntry(
StringUtils.removeStart( path, "/" ) + ".war"
)
);
这对于配置的<path>/<path>
将转换为“.war”作为文件名看起来更合法,但仍然不是真正理想的imho。
由于Tomcat 7 Documentation声明空的上下文路径(又名“/”)的基本文件名应该是ROOT
,最好的选择是选择<path>ROOT<path>
来实现所需的结果。
编辑:
为了复制这个,我检查了tomcat-maven-plugin.git并使用了their integration test。我有一些完整的功能构建,在从server.xml中删除一些东西并将tomcat7-maven-plugin版本更改为2.1后,它有点工作:
这是应用于其集成测试应用程序的差异:
diff --git a/tomcat7-maven-plugin/src/it/simple-war-exec-project/pom.xml b/tomcat7-maven-plugin/src/it/simple-war-exec-project/pom.xml
index 8ce51b7..e00f0ea 100644
--- a/tomcat7-maven-plugin/src/it/simple-war-exec-project/pom.xml
+++ b/tomcat7-maven-plugin/src/it/simple-war-exec-project/pom.xml
@@ -42,7 +42,7 @@
<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat7-maven-plugin</artifactId>
- <version>@pom.version@</version>
+ <version>2.1</version>
</plugin>
</plugins>
</pluginManagement>
@@ -65,7 +65,7 @@
</goals>
<phase>package</phase>
<configuration>
- <path>foo</path>
+ <path>ROOT</path>
<serverXml>src/main/tomcatconf/server.xml</serverXml>
</configuration>
</execution>
diff --git a/tomcat7-maven-plugin/src/it/simple-war-exec-project/src/main/tomcatconf/server.xml b/tomcat7-maven-plugin/src/it/simple-war-exec-project/src/main/tomcatconf/server.xml
index 76ab562..de086fc 100644
--- a/tomcat7-maven-plugin/src/it/simple-war-exec-project/src/main/tomcatconf/server.xml
+++ b/tomcat7-maven-plugin/src/it/simple-war-exec-project/src/main/tomcatconf/server.xml
@@ -19,14 +19,7 @@
<Server port="8010" shutdown="SHUTDOWN">
- <GlobalNamingResources>
- <!-- Used by Manager webapp -->
- <Resource name="UserDatabase" auth="Container"
- type="org.apache.catalina.UserDatabase"
- description="User database that can be updated and saved"
- factory="org.apache.catalina.users.MemoryUserDatabaseFactory"
- pathname="conf/tomcat-users.xml" />
- </GlobalNamingResources>
+
<Service name="Catalina">
<Connector port="8080" keepAliveTimeout="1800000" maxKeepAliveRequests="30000" maxThreads="300" />
@@ -34,8 +27,6 @@
<Engine name="Catalina" defaultHost="localhost">
<Valve className="org.apache.catalina.valves.AccessLogValve"
resolveHosts="false" pattern="%t-ip:%a-protocol:%H-localPort:%p-path:%U-time:%D ms"/>
- <Realm className="org.apache.catalina.realm.UserDatabaseRealm"
- resourceName="UserDatabase" />
<Host name="localhost" appBase="webapps" />
</Engine>
然后从文件夹/tomcat-maven-plugin/tomcat7-maven-plugin/src/it/simple-war-exec-project
我做了:
$ mvn clean package
...
[INFO] BUILD SUCCESS
...
$ cd target/
$ java -jar simple-war-exec-project-1.0-SNAPSHOT-war-exec.jar
...
INFORMATION: Deploying web application archive C:\Temp\tomcat-maven-plugin\tomcat7-maven-plugin\src\it\simple-war-exec-project\target\.extract\webapps\ROOT.war
...
结果如下: