给定以下 MultiIndex df
|富 | | |一个 |两个 | | ------ | ------ | | “12345” | “1235” | | “12345” | “1345”|
我想追加更多列,每个列都填充相同的值,但不同列的值不同。我将这些值按以下方式存储为 MultiIndex pandas Series se:
|酒吧| 0 | 2 | | | 1 | 3 | ………… | | 99 | 7 |
结果将如下所示: |富 | |酒吧 | | ... | | |一个 |两个 | 0 | 1 | ... | 99 | | ------ | ------ | --- | --- | ... | --- | | “12345” | “1235” | 2 | 3 | ... | 7 | | “12345” | “1345” | 2 | 3 | ... | 7 |
我发现这个非常丑陋的解决方案...
for i in range(len(se)):
df["bar", i] = se[i]
...这也给了我一个警告:
PerformanceWarning: DataFrame is highly fragmented. This is usually the result of calling
frame.insertmany times, which has poor performance. Consider joining all columns at once using pd.concat(axis=1) instead. To get a de-fragmented frame, use
newframe = frame.copy()``
一段时间以来一直在努力寻找解决方案,在此先感谢您提供有用的答案!