Node JS：按数组分组循环

Question

我有这样的数据

[
  [ '@test','1.2.6-unstable' ],
  [ '@test','1.3.2-unstable' ],
  [ '@test','1.4.6-unstable' ],
  [ '@test2','4.0.1-unstable' ],
  [ '@test2','4.0.2-unstable' ],
  [ '@test2','4.0.3-unstable' ],
  [ '@test3','2.2.0-unstable' ],
  [ '@test3','2.2.3-unstable' ],
  [ '@test3','2.2.9-unstable' ],
...
]

并且我尝试按名称对它们进行分组

@test

，然后循环这些值并对每个值应用一个操作，忽略第一个值。 我的输出应该是

[
  [ '@test','1.3.2-unstable' ],
  [ '@test','1.4.6-unstable' ]
]

[
  [ '@test2','4.0.2-unstable' ],
  [ '@test2','4.0.3-unstable' ]
]

[
  [ '@test3','2.2.3-unstable' ],
  [ '@test3','2.2.9-unstable' ]
]

我已经查看了这些问题，但我无法应用正确的组合来获得我需要的东西
根据属性将对象数组分解为单独的数组
无法在 JS 中循环分组数组
JS用map循环遍历数组和组
我也尝试过

.shift()

和

.slice(1)

但这只会从整个原始数组中取出第一个

我的代码如下所示：

const response = await axios.get(reportURL, { headers });
const mystuff = response.data.value.reduce((acc, next) => {
  acc.push(...next.versions.map((v) => [next.name, v.version]));
  return acc;
}, []);
const filteredArray = mystuff.filter(([_, version]) => version.includes('-unstable'));
const map = filteredArray.reduce((acc, { name, version }) => {
  if (acc.has(name)) {
    acc.get(name).versions.push(version);
  } else {
    acc.set(name, { name, versions: [version] });
  }
  return acc;
}, new Map());

const result = [...map.values()];

// Loop round the array and fire off the axios
result.forEach(([name, version]) => {
  const URL = `https:URL/${name}/versions/${version}?api-version=7.1-preview.1`;

Answer 1

我在下面添加示例代码

const data = [
  ["@test", "1.2.6-unstable"],
  ["@test", "1.3.2-unstable"],
  ["@test", "1.4.6-unstable"],
  ["@test2", "4.0.1-unstable"],
  ["@test2", "4.0.2-unstable"],
  ["@test2", "4.0.3-unstable"],
  ["@test3", "2.2.0-unstable"],
  ["@test3", "2.2.3-unstable"],
  ["@test3", "2.2.9-unstable"],
  // ... more data
];

const groupedData = new Map();

data.forEach(([name, version], index) =>
  groupedData.has(name)
    ? groupedData.get(name).push([name, version])
    : groupedData.set(name, [])
);

groupedData.forEach((group) => console.log(group));

Answer 2

您可以使用

Object.groupBy

按嵌套数组的第一项进行分组，并仅获取值。

const
    data = [['@test','1.2.6-unstable'], [ '@test','1.3.2-unstable'], ['@test','1.4.6-unstable'], ['@test2','4.0.1-unstable' ], ['@test2','4.0.2-unstable'], ['@test2','4.0.3-unstable'], ['@test3','2.2.0-unstable'], ['@test3','2.2.3-unstable'], ['@test3','2.2.9-unstable']],
    grouped = Object.values(Object.groupBy(data, ([first]) => first));

console.log(grouped);

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