我有以下,如果存在platform
施加一个WHERE语句的外生查询。
defp maybe_platform(queryable, false), do: queryable
defp maybe_platform(queryable, platform) do
queryable
|> where([c], c.platform == ^platform)
end
我怎么可以概括为任何变量(而不是仅仅platform
)这个代码? (它是c.platform
位,我挣扎)
您需要使用Ecto field
https://hexdocs.pm/ecto/Ecto.Query.API.html#field/2
你的函数将是这个样子
defp maybe_field(queryable, field_name, field_value) do
queryable
|> where([c], field(c, ^field_name) == ^field_value)
end
接着
(from m in MyModel)
|> maybe_field(:platform, "platform_name_or_variable")
|> maybe_field(:another_field, "some value")
|> maybe_field(:is_platform_enabled, true)
|> Repo.all
您可以使用关键字作为过滤。看一看Ecto.Query#where/3:
from(c in City, where: c.country == "Sweden")
from(c in City, where: [country: "Sweden"])
Ecto.Query.where/3
接受关键字列表的过滤器。药剂关键字列表仅仅是围绕每两个元素的元组的列表二郎的包装。这就是说,有点像会做:
defp maybe_where(queryable, _param, false), do: queryable
defp maybe_where(queryable, param, value) do
filters = [{param, value}]
where(queryable, ^filters)
end