我正在使用SVR来预测NBA幻想得分。我的indep变量添加到我的dep变量中。
import numpy as np
import pandas as pd
DK = pd.read_csv('NV.csv')
X = DK.iloc[:, :-1].values.astype(float)
Y = DK.iloc[:,9].values.astype(float).reshape(-1,1)
#Feature Scaling
from sklearn.preprocessing import StandardScaler
sc_X = StandardScaler()
sc_y = StandardScaler()
X = sc_X.fit_transform(X)
Y = sc_y.fit_transform(Y)
#Fitting SVR to data and creating regressors
from sklearn.svm import SVR
regressor1 = SVR(kernel='rbf')
regressor1.fit(X,Y)
DataConversionWarning: A column-vector y was passed when a 1d array was expected. Please change the shape of y to (n_samples, ), for example using ravel().
y = column_or_1d(y, warn=True)
SVR(C=1.0, cache_size=200, coef0=0.0, degree=3, epsilon=0.1, gamma='auto',
kernel='rbf', max_iter=-1, shrinking=True, tol=0.001, verbose=False)
预测新结果将导致我的代码遇到障碍
y_pred = sc_y.inverse_transform((regressor1.predict(sc_X.transform(np.array([[6.5]])))))
这将返回以下错误。是我如何拟合/缩放数据或完全不同的问题?
ValueError Traceback (most recent call last)
<ipython-input-63-9c7f8b557a70> in <module>
----> 1 y_pred = sc_y.inverse_transform((regressor1.predict(sc_X.transform(np.array([[1.9]])))))
~\Anaconda\lib\site-packages\sklearn\preprocessing\data.py in transform(self, X, copy)
767 else:
768 if self.with_mean:
--> 769 X -= self.mean_
770 if self.with_std:
771 X /= self.scale_
ValueError: non-broadcastable output operand with shape (1,1) doesn't match the broadcast shape (1,9)
首先了解错误本身:
X -= self.mean_
我可以通过以下方式重现错误:
In [234]: X = np.array([[1.23]])
In [235]: X.shape
Out[235]: (1, 1)
In [236]: X -= np.array([[1,2,3]])
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-236-6854fd7cd554> in <module>
----> 1 X -= np.array([[1,2,3]])
ValueError: non-broadcastable output operand with shape (1,1) doesn't match the broadcast shape (1,3)
我要写的是将回溯备份到您自己的代码可能需要一些工作。但我看到了您自己的代码:
sc_X.transform(np.array([[6.5]]))
[np.array([[6.5]])
最有可能是(1,1)数组,X
。