如何用Gson序列化java.nio.file.Path?

问题描述 投票:0回答:2

尝试序列化包含

java.lang.StackOverflowError
Object
 时,我得到 
java.nio.file.Path

即使我写道:

public class PathConverter implements JsonDeserializer<Path>, JsonSerializer<Path> {
    @Override
    public Path deserialize(JsonElement jsonElement, Type type, JsonDeserializationContext jsonDeserializationContext) throws JsonParseException {
        return Paths.get(jsonElement.getAsString());
    }

    @Override
    public JsonElement serialize(Path path, Type type, JsonSerializationContext jsonSerializationContext) {
        return new JsonPrimitive(path.toString());
    }
}

并应用它:

    String json = new GsonBuilder()
            .registerTypeAdapter(Path.class, new PathConverter())
            .create()
            .toJson(constructorSetup, new TypeToken<ConstructorSetup>() {}.getType());

我仍然无法序列化这个类:

public class ConstructorSetup {

    private Path appIconMimmapDirPathOnPc;

}

Stacktrace:(完整的pastebin

Exception in thread "main" java.lang.StackOverflowError
    at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:380)
    at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:375)
    at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:380)
        ...
    at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:380)
    at com.google.gson.internal.$Gson$Types.resolve($Gson$Types.java:355)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.getBoundFields(ReflectiveTypeAdapterFactory.java:117)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.create(ReflectiveTypeAdapterFactory.java:72)
    at com.google.gson.Gson.getAdapter(Gson.java:356)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$1.<init>(ReflectiveTypeAdapterFactory.java:82)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.createBoundField(ReflectiveTypeAdapterFactory.java:81)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.getBoundFields(ReflectiveTypeAdapterFactory.java:118)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.create(ReflectiveTypeAdapterFactory.java:72)
    at com.google.gson.Gson.getAdapter(Gson.java:356)
        ...
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$1.<init>(ReflectiveTypeAdapterFactory.java:82)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.createBoundField(ReflectiveTypeAdapterFactory.java:81)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.getBoundFields(ReflectiveTypeAdapterFactory.java:118)
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory.create(ReflectiveTypeAdapterFactory.java:72)
    at com.google.gson.Gson.getAdapter(Gson.java:356)

有什么解决办法吗?

java gson nio
2个回答
13
投票

你的问题是

Path
是一个
interface
。假设您使用了
Paths.get("/")
,它将在我的 Windows PC 上创建类似
WindowsPath
的实例。现在,您必须告诉 GSON 如何反序列化此类型:

ConstructorSetup setup = new ConstructorSetup();
setup.setAppIconMimmapDirPathOnPc(Paths.get("/"));

// here we get actual class type of our Path object
Class classT = setup.getAppIconMimmapDirPathOnPc().getClass();

Gson gson = new GsonBuilder().registerTypeAdapter(classT, new MyPathConverter())

您可以采用的另一种方法是

registerTypeHierarchyAdapter

.registerTypeHierarchyAdapter(Path.class, new MyPathConverter())

typeHierarchyAdapter 的目的是覆盖当您希望类型的所有子类型具有相同表示形式时的情况,这正是您使用

Path
的情况。


0
投票

MyPathConverter 实现了 Path 接口。

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