触发器上的旋转去c＃unity

Question

我正在寻找一个游戏对象在按下眼球上的触发器时旋转，但只有这样，我有以下代码。不幸的是，即使我把手指从触发器上移开，这也会持续不断

public GameObject dummyrotate;
private bool rotate = false;
float rotationAmount = .3f;
float delaySpeed = .1f;


public void rotateAntiClockwise()

{
    StartCoroutine(SlowSpin2());
}

public IEnumerator SlowSpin2()

{
    float count = 0;
    while (count <= 90)

    {
        dummyrotate.transform.Rotate(new Vector3(0,-rotationAmount,0));
        count += rotationAmount;
        yield return new WaitForSeconds(delaySpeed);
    }
}

非常感谢Jono

Answer 1

如果你只是想在按住触发器时旋转它，那就不要使用协程。协同程序将一直运行，直到它们完成，所以改为尝试这样的事情：

public GameObject dummyrotate;
private bool rotate = false;
float rotationAmount = .3f;
float delaySpeed = .1f;


void Update()
{
    SlowSpin2();
}

public void SlowSpin2()

{
    if (rotate == true) {
        dummyrotate.transform.Rotate(new Vector3(0,-rotationAmount,0));
        count += rotationAmount;
    }
}

Answer 2

那么问题是，一旦你触发旋转，你需要30秒来完成你的coroutine因为你的while循环。而当你再次触发它时，你会开始另一个coroutine，这将永远像这样继续。我假设每次按下触发器时都会调用rotateAntiClockwise方法。

我也假设您想要在y轴上旋转90度，您可以像这样实现：

 bool isRunning = false;
 //Make sure this variable is true when triggered and false when not
 bool isTrigger = false;
 float rotationAmount = 0.3f;
 public IEnumerator SlowSpin2()
 {
    isRunning = true;
    //This will rotate the object continuously until isTriggered is false
    while (isTriggered)
    {
        Debug.Log("Rotating");
        transform.Rotate(new Vector3(0, -rotationAmount, 0));            
        yield return null;

    }
    Debug.Log(Time.time);
    isRunning = false;
 }

此脚本将在2秒内将对象从0缓慢旋转到90。

然后你必须像这样修改你的rotateAntiClockwise，所以当这个已经运行时你不会启动另一个协同程序。

public void rotateAntiClockwise()
{
     if(!isRunning)
         StartCoroutine(SlowSpin2());
}