我有一个叫做feature / xyz的分支。现在,我必须将文件名从filename.exe命名为filename_ $ BRANCH_NAME.exe
但是问题出在这里,因为我的分支名称前有斜杠,所以会抛出错误。
所以如何将我的文件命名为filename_feature_xyz?
下面的代码示例。本质上,您只可以使用字符串替换功能。但是,它进一步满足了未知的文件名,该文件名符合您在示例中列出的约定。
#!groovy
// Setup vars to replicate your questions specs
env.BRANCH_NAME = "feature/xyz"
String file = 'filename.exe'
// Replace any forward slash with an underscore
String branchName = (env.BRANCH_NAME).replace('/', '_')
// Split apart your current filename
List fileParts = file.tokenize('.')
// Construct the original filename, catering for multiple period usecases
String originalFileName = fileParts[0..-2].join('.')
// Seperate the extension for use later
String originalExtension = fileParts[-1]
// Combine into the desired filename as per your requirements
String newFileName = "${originalFileName}_${branchName}.${originalExtension}"