Mingw-w64 gcc编译器为什么会生成关于％zd和％a格式的错误警告>> [

Question

我正在使用gcc编译器，命令行为

{gcc 'hellowo.c' -o 'hellowo.exe' -Wall -g -O2 -static-libgcc -std=c11 -fexec-charset=GBK}

并且版本信息是

gcc version 8.1.0 (x86_64-win32-seh-rev0, Built by MinGW-W64 project)

当我尝试时

#include <stdio.h>

int main(void)
{
    float float1 = 64.25f;
    printf("%zd\n",sizeof(int));
    printf("%a",float1); //float1=64.25f
    return 0;
}

编译器警告我：

hellowo.c: In function 'main':
hellowo.c:6:12: warning: unknown conversion type character 'z' in format [-Wformat=]
     printf("%zd\n",sizeof(int));
            ^~~~~~~
hellowo.c:6:12: warning: too many arguments for format [-Wformat-extra-args]
hellowo.c:6:12: warning: unknown conversion type character 'z' in format [-Wformat=]
hellowo.c:6:12: warning: too many arguments for format [-Wformat-extra-args]
hellowo.c:7:12: warning: unknown conversion type character 'a' in format [-Wformat=]
     printf("%a",float1); //float1=64.25f
            ^~~~
hellowo.c:7:12: warning: too many arguments for format [-Wformat-extra-args]
hellowo.c:7:12: warning: unknown conversion type character 'a' in format [-Wformat=]
hellowo.c:7:12: warning: too many arguments for format [-Wformat-extra-args]

但是输出是

4
0x1.010000p+6

为什么会发生这种情况，我正在使用
C引物加

的示例自行研究]很奇怪，.exe可以正常工作，并且我的程序可以成功编译。

我尝试将％zd修改为％zu，（“％zd”语句是

C引物加

的示例]仍然有警告：

hellowo.c:6:12: warning: unknown conversion type character 'z' 
in format [-Wformat=]
     printf("%zu\n",sizeof(int));
            ^~~~~~~
hellowo.c:6:12: warning: too many arguments for format [-Wformat-extra-args]
hellowo.c:6:12: warning: unknown conversion type character 'z' 
in format [-Wformat=]
hellowo.c:6:12: warning: too many arguments for format [-Wformat-extra-args]

Mingw-w64 gcc编译器为什么会生成关于％zd和％a格式的错误警告？

我正在使用gcc编译器，命令行为{gcc'hellowo.c'-o'hellowo.exe'-Wall -g -O2 -static-libgcc -std = c11 -fexec-charset = GBK}和该版本信息是gcc版本8.1.0（x86_64 -...

Answer 1

这是不完整的答案。