我有两个kendo可排序列表,列表A和列表B.列表A有固定对象(item1,item2,item3),列表B为空。每次我将一个对象从列表A拖到列表B时,我想要克隆到列表B中。
我注意到,如果我尝试将相同的项目拖动两次或更多次,它始终是列表A中列出的同一对象的副本。
如何将对象从列表A拖到列表B克隆呢?
谢谢
我确实对你的kendo sortable的查询有所了解,但是由于调色板数组被刷新而无法获得任何正常工作的代码,但是我无法获得可排序的刷新以显示更新的数据;不过你可以尝试这样的事情。当您将项目从A移动到B时,它将从A中删除并添加到B,但是您可以阻止默认并让A保留该项目并将新数据项添加到B.我使用了可排序的Data add event
import { Component, ViewEncapsulation, Input } from '@angular/core';
import { DataEvent, DragStartEvent, DragEndEvent, DragOverEvent, NavigateEvent } from '@progress/kendo-angular-sortable';
@Component({
selector: 'my-app',
template: `
<div class="example-config">
<h5>Team A: {{palettes.TeamA | json}}</h5>
<h5>Team B: {{palettes.TeamB | json}}</h5>
</div>
<div class="container-fluid">
<div class="row">
<div class="col-xs-12 col-sm-6 team">
<h5>Team A</h5>
<kendo-sortable
[kendoSortableBinding]="palettes.TeamA"
zone="twoWay"
emptyText="Move employees from Team B to Team A."
class="row"
itemClass="employee"
[emptyItemStyle]="{'min-height': '150px', width:'100%'}"
emptyItemClass="empty"
activeItemClass="employee active">
</kendo-sortable>
</div>
<div class="col-xs-12 col-sm-6 team team-b">
<h5>Team B</h5>
<kendo-sortable [kendoSortableBinding]="palettes.TeamB"
zone="twoWay"
emptyText="Move employees from Team A to Team B."
class="row"
itemClass="employee"
[emptyItemStyle]="{'min-height': '150px', width:'100%'}"
emptyItemClass="empty"
activeItemClass="employee active"
(dataAdd)="onDataAdd('TeamA','TeamB', $event)">
</kendo-sortable>
</div>
</div>
</div>
`,
styleUrls: ['styles.css'],
encapsulation: ViewEncapsulation.None
})
export class AppComponent {
@Input() textContent;
public palettes = {
'TeamA': ['Peter Franken', 'Simon Crowther', 'Catherine Dewey','Lino Rodriguez', 'Paolo Accorti'],
'TeamB': []
};
public onDataAdd(src: string, dest: string, e: any): void {
e.preventDefault();
this.palettes[dest].push(e.dataItem);
}
}