我想在字符串中找到某个结构的所有结果,最好使用正则表达式。
要查找所有网址,可以使用
re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', decode)
然后它回来了
'https://en.wikipedia.org'
我想要一个正则表达式字符串,它找到:
href="/wiki/*anything*"
OP:开头必须是href =“/ wiki / middle可以是任何东西,最终必须是”
st = "since-OP-did-not-provide-a-sample-string-34278234$'blahhh-okay-enough.href='/wiki/anything/everything/nothing'okay-bye"
print(st[st.find('href'):st.rfind("'")+1])
OUTPUT:
href='/wiki/anything/everything/nothing'
编辑:
如果我们要解析html,我会选择BeautifulSoup。
from bs4 import BeautifulSoup
text = '''<a href='/wiki/anything/everything/nothing'><img src="/hp_imgjhg/411/1/f_1hj11_100u.jpg" alt="dyufg" />well wait now <a href='/wiki/hello/how-about-now/nothing'>'''
soup = BeautifulSoup(text, features="lxml")
for line in soup.find_all('a'):
print("href =",line.attrs['href'])
OUTPUT:
href = /wiki/anything/everything/nothing
href = /wiki/hello/how-about-now/nothing