这是一个简化的表结构:
TABLE products (
product_id INT (primary key, auto_increment),
category_id INT,
product_title VARCHAR,
etc
);
TABLE product_photos (
product_photo_id (primary key, auto_increment),
product_id INT,
photo_href VARCHAR,
photo_order INT
);
一个产品可以有多张照片,每个产品的第一张产品照片(根据photo_order)为默认照片。
现在,我只需要产品详细信息页面上的所有照片,但在列出多个产品的页面上,例如产品目录页面,我只想显示默认照片。
所以我想做的是查询产品列表,包括每个产品的默认照片。
这显然不起作用,它将返回所有照片,并为每张照片重复产品信息:
SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
ON p.product_id=ph.product_id
ORDER BY p.product_title ASC
我需要弄清楚如何做这样的事情,但我不知道语法(或者是否可能)
SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
ON p.product_id=ph.product_id **ORDER BY ph.photo_order ASC LIMIT 1**
ORDER BY p.product_title ASC
编辑:我在下面的答案的帮助下找到了解决方案,谢谢大家!
SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
ON p.product_id=ph.product_id
AND ph.photo_order =
(
SELECT MIN(z.photo_order)
FROM product_photos AS z
WHERE z.product_id=p.product_id
)
GROUP BY p.product_id
ORDER BY p.product_title ASC
SELECT p.*, ph.*
FROM products AS p
INNER JOIN product_photos AS ph
ON p.product_id = ph.product_id
LEFT JOIN product_photos AS ph2
ON p.product_id = ph2.product_id
AND ph2.photo_order < ph.photo_order
WHERE ph2.photo_order IS NULL
ORDER BY p.product_title ASC
注意它如何两次连接到product_photos 表。
WHERE ph2.photo_order IS NULL
将丢弃除最低照片顺序之外的所有照片。不过,它不会保护您免受重复的product_id / photo_orders组合的影响,如果是这种情况,您可以在p.id上添加GROUP BY
。
用途:
SELECT p.*,
pp.*
FROM PRODUCTS p
JOIN PRODUCT_PHOTOS pp ON pp.product_id = p.product_id
JOIN (SELECT x.product_id,
MIN(x.photo_order) AS default_photo
FROM PRODUCT_PHOTOS x
GROUP BY x.product_id) y ON y.product_id = pp.product_id
AND y.default_photo = pp.photo_order
SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph ON p.product_id=ph.product_id
ORDER BY p.product_title ASC, ph.photo_order ASC
GROUP BY p.product_id
LIMIT 0,10
SELECT ...
....
GROUP BY p.product_id